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Charra [1.4K]
4 years ago
6

Maggie only wore sandals tracker on two of the days that she trained so from her fitness trackers she verified that on the third

day she biked 20 miles and on the eighth day she biked 35 miles use these two data points to determine the equation of the line best of fit set for Maggie’s data
Mathematics
1 answer:
KIM [24]4 years ago
3 0
We know form our problem that the third day she biked 20 miles, so we have the point (3,20). We also know that <span>on the eighth day she biked 35 miles, so our second point is (8,35).

To relate our two point we are going to use the slope formula: </span>m= \frac{x_{2}-x_{1}}{y_{2}-y_{1}}
We can infer form our points that x_{1}=3, y_{1}=20,x_{2}=8, and y_{2}=35. so lets replace those values in our slope formula:
m= \frac{35-20}{8-3}
m= \frac{15}{5}
m=3

Now that we have the slope, we can use the point-slope formula <span>determine the equation of the line that best fit the set for Maggie’s data.
Point-slope formula: </span>y-y_{1}=m(x-x_{1})
y-20=3(x-3)
y-20=3x-9
y=3x+11

We can conclude that the equation of the line that  best fit the set for Maggie’s data is y=3x+11.
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Step-by-step explanation:

52.149

Since last digit is 9,

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podryga [215]

Answer:

y = 4

Step-by-step explanation:

Use the distributive property to multiply all terms in the parentheses by 4

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I don't understand math @ all please help
chubhunter [2.5K]
More than likely it is c, because I looked over all the answers and c was the best one for the problem
7 0
3 years ago
The minimum of the graph of a quadratic function is located at (–1, 2). The point (2, 20) is also on the parabola. Which functio
Stels [109]
<span>Minimum wykresu funkcji kwadratowej znajduje się w ( -1, 2). Punkt ( 2 , 20) jest również od paraboli. Która funkcja reprezentuje sytuację?
</span><span>Canonical form of the function
</span>f(x) = a* (x - p)² + q

A .f(x) = (x + 1)² + 2    ⇔ p= -1 , q = 2
B. f(x) = (x – 1)² + 2    we reject
C. f(x) = 2(x + 1)² + 2  ⇔ p = -1 , q = 2
D .f(x) = 2(x – 1)² + 2   we reject

The point (2,20)  substitute
A f(x) = (x +1)² + 2
   20 = (2 + 1 )² + 2
   20 ≠ 9 +2
   20 ≠ 11   we reject

D f(x) = 2* (x + 1)² + 2
    20 = 2* (2+1)² + 2
    20 = 2 * 3² + 2
    20 = 2 * 9 + 2
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Reply C

8 0
4 years ago
for a graph of a quadratic i have x intercepts that are x=12 and x =35 do i have enough information to find the y-coordinate of
goldenfox [79]

Answer:

No... provided no other information or no graph is provided.

Step-by-step explanation:

You can find the x-coordinate of the vertex which can be calculated using the two given x-intercepts. Using the symmetry of the parabola, it would just mean the vertex should lay midway between the x's. So the x-coordinate of the vertex is (12+35)/2=47/2.

However, we do not have enough information about the relationship between x and y to find the y-coordinate of the vertex.

All we are given is y=a(x-12)(x-35) (where a is real number) since we know the relationship is quadratic, and the zeros are 12 & 35.

So we could have many possible y-coordinates for our vertex since we don't know the value of a in our equation and we can plug in our x-coordinate for our vertex to find them all.

y=a(47/2-12)(47/2-35)

I'm just going to put everything to right of a in calculator:

y=-529/4 ×a

So that's all the possible y-coordinates for the vertex.

7 0
3 years ago
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