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lubasha [3.4K]
3 years ago
10

Sharon wants to name her website sharonworld.com. What should she do next? A. begin searching for images to make her website loo

k attractive B. begin writing website content C. list the objectives of her website D. purchase space on a web server E. purchase the domain name
Computers and Technology
2 answers:
timama [110]3 years ago
4 0

Answer:

E, Purchase the domain name.

Explanation:

You want to have your websites name filed so nobody can take it from you.

Goshia [24]3 years ago
3 0

purchase the domain name

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a) (20 points) Define the method inDogish recursively such that it returns true if the word is in dog-ish and false if it is not
tia_tia [17]

Answer:

/ Main.java

class Main {

     public static void main(String[] args) {

           //System.out.println(inDogish("aplderogad"));

           //System.out.println(inXish("aplderogad", "dog"));

     }

     // returns true if the word is in dog-ish

     // returns false if word is not in dog-ish

     public static boolean inDogish(String word) {

           /**

           * Note: we can use the inXish() method to complete this method in a

           * single line if you want. just write 'return inXish(word,"dog");' and

           * you are done.

           */

           // if word is null or empty, returning false

           if (word == null || word.length() == 0) {

                 return false;

           }

           // converting word to lower case

           word = word.toLowerCase();

           // if 'd' does not exist on the word, returning false

           if (!dogishHelper(word, 'd')) {

                 return false;

           }

           // removing the characters upto first 'd' in word

           word = word.substring(word.indexOf('d') + 1);

           // if 'o' does not exist on the word, returning false

           if (!dogishHelper(word, 'o')) {

                 return false;

           }

           // removing the characters upto first 'o' in word

           word = word.substring(word.indexOf('o') + 1);

           // if 'g' does not exist on the word, returning false, otherwise

           // returning true

           if (!dogishHelper(word, 'g')) {

                 return false;

           } else {

                 return true;

           }

     }

     // necessary to implement inDogish recursively.

     // returns true if letter is in word, else not.

     public static boolean dogishHelper(String word, char letter) {

           // if word is empty, returning -1

           if (word == null || word.length() == 0) {

                 return false;

           }

           // if first character in word is letter, returning 0

           if (word.charAt(0) == letter) {

                 return true;

           }

           return dogishHelper(word.substring(1), letter);

     }

     // the best thing about the above helper method is that we can use it in

     // inXish method also

     // a generalized version of the inDogish method

     public static boolean inXish(String word, String x) {

           // if x is empty, returning true (base case, which means all the letters

           // in x are in word in that order)

           if (x.length() == 0) {

                 return true;

           }

           // getting first character of x

           char first = x.charAt(0);

           // if first character does not exist on the word, returning false

           if (!dogishHelper(word, first)) {

                 return false;

           }

           // calling and returning inXish recursively, passing the word after

           // removing characters upto first occurrance of char first, and x after

           // removing first character from it

           return inXish(word.substring(word.indexOf(first) + 1), x.substring(1));

     }

}

Explanation:

7 0
4 years ago
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