Answer:
a). M = 20.392 kg
b). am = 0.56 (block), aM = 0.28 (bucket)
Explanation:
a). We got N = mg cos θ,
f =
=
If the block is ready to slide,
T = mg sin θ + f
T = mg sin θ + .....(i)
2T = Mg ..........(ii)
Putting (ii) in (i), we get
M = 20.392 kg
b). .............(iii)
Here, l = total string length
Differentiating equation (iii) double time w.r.t t, l, h and h' are constants, so
.....................(iv)
We got, N = mg cos θ
∴
................(v)
Mg - 2T = M
(from equation (iv))
.....................(vi)
Putting (vi) in equation (v),
Using equation (iv), we get,
The acceleration of gravity on Jupiter is listed as <em>24.79 m/s²</em> .
That's roughly 2.53 times its value on Earth. So if you weigh, let's say,
130 pounds on Earth, then you would weigh about 328 pounds on Jupiter.
Answer:
The period of that same pendulum on the moon is 12.0 seconds.
Explanation:
To determine the period of that same pendulum on the moon,
First, we will determine the value of g (which is a measure of the strength of Earth's gravity) on the Moon. Let the value of g on the Moon be .
From the question, the strength of earth’s gravity is only 1/6th of the normal value. The normal value of g is 9.8 m/s²
∴ =
= 1.63 m/s²
From the question, T=2π√L/g
We can write that,
.......... (1)
Where is the period of the pendulum on Earth and is the measure of the strength of Earth's gravity
and
.......... (2)
Where is the period of the pendulum on Moon and is the measure of the strength of Earth's gravity on the Moon.
Since we are to determine the period of the same pendulum on the moon, then, and are constants.
Dividing equation (1) by (2), we get
From the question,
= 9.8 m/s²
= 1.63 m/s²
= ??
From,
∴
Hence, the period of that same pendulum on the moon is 12.0 seconds.
I would say all of them, because when making an observation you use, sight,sound,taste,touch, and smell
When it reaches it's peak, the energy is converted into potential as it slows down, then back to kinetic as it goes back to the lowest point.