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2 years ago

How might you use a rope and pulley to move a wagon up a ramp?

1 answer:

7 0

You could attach the pulley to a secure object on the top of the ramp, and crank the pulley to bring the wagon up said ramp into a loading bay perhaps, or a track.

Hope I helped.

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a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d

Illusion [34]

Answer:

239 rpm

Explanation: So the distance covered in one minute is 75,000 centimeters. The diameter of the wheel is 100 cm, so the radius is 50 cm, and the circumference is 100π cm. How many of these circumferences (or wheel revolutions) fit inside the 75,000 cm? In other words, if I were to peel this wheel's tread from the cart and lay it out flat, it would measure a distance of 100π cm. How many of these lengths fit into the entire distance covered in one minute? To find out how many of (this) fit into so many of (that), I must divide (that) by (this), so:

100πcm/rev

75,000cm/min

750 min rev≈238.7324146RPM

5 0

2 years ago

Tsunami waves have ?

mr Goodwill [35]

I think it #3(not Sure) I think Its because of their long wavelengths that tsunamis behave as shallow-water waves.

4 0

3 years ago

10 Points!

Zinaida [17]

The kinetic energy gets faster as the atoms move faster. Atoms move faster when heat is applied and more slower when they cool.

4 0

2 years ago

Read 2 more answers

To increase the acceleration on the new station due to Earth's gravity, you decide

____ [38]

To increase the acceleration due to gravity, we will place the new station in a shorter radius which is 1.2 RE.

<h3>What is acceleration due to gravity?</h3>

This is free fall of an object under the influence of gravitational pull.

The acceleration due to gravity of the new station due to Earth's gravity is calculated as follows;

$g = \frac{GM}{R^2}$

where;

g is the acceleration due to gravity
G is gravitational constant
M is the mass of the earth
R is the radius of the earth

To increase the acceleration due to gravity, the radius of the earth must be decreased. Thus, we will place the new station in a shorter radius which is 1.2 RE.

Learn more about acceleration due to gravity here: brainly.com/question/88039

6 0

2 years ago

g You drop a 3.6-kg ball from a height of 3.5 m above one end of a uniform bar that pivots at its center. The bar has mass 9.9 k

Salsk061 [2.6K]

Answer:

h = 3.5 m

Explanation:

First, we will calculate the final speed of the ball when it collides with a seesaw. Using the third equation of motion:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 3.5 m

vf = final speed = ?

vi = initial speed = 0 m/s

Therefore,

$(2)(9.81\ m/s^2)(3.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{68.67\ m^2/s^2}\\v_f = 8.3\ m/s$

Now, we will apply the law of conservation of momentum:

$m_1v_1 = m_2v_2$

where,

m₁ = mass of colliding ball = 3.6 kg

m₂ = mass of ball on the other end = 3.6 kg

v₁ = vf = final velocity of ball while collision = 8.3 m/s

v₂ = vi = initial velocity of other end ball = ?

Therefore,

$(3.6\ kg)(8.3\ m/s)=(3.6\ kg)(v_i)\\v_i = 8.3\ m/s$

Now, we again use the third equation of motion for the upward motion of the ball:

$2gh = v_f^2 - v_i^2\\$

where,

g = acceleration due to gravity = -9.81 m/s² (negative for upward motion)

h = height = ?

vf = final speed = 0 m/s

vi = initial speed = 8.3 m/s

Therefore,

$(2)(9.81\ m/s^2)h = (0\ m/s)^2-(8.3\ m/s)^2\\$

6 0

2 years ago