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mariarad [96]
3 years ago
6

A 300.0 W immersion heater is used to heat 0.250 kg of water from 10.0 °C to 70.0 °C. About how many seconds did this take? (T

here are 4186 Joules per kcal.)
Physics
1 answer:
Anika [276]3 years ago
4 0

Answer:

209.3 seconds

Explanation:

P = 300 W, m =  0.250 kg, T1 = 10 degree C, T2 = 70 degree C

c = 4186 J / kg C

Heat given to water = mass x specific heat of water x rise in temperature

H = 0.250 x 4186 x (70 - 10)

H = 62790 J

Power = Heat / Time

Time, t = heat / Power

t = 62790 / 300 = 209.3 seconds

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ig so it's already heated

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Which of the following activities best illustrates the nature of a dialectical process?
galina1969 [7]
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3 years ago
Who is son of nation ​
igor_vitrenko [27]

Explanation:

well the father of nation is Mahtma Gandhi.

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3 years ago
An ideal heat engine absorbs heat at 100°C and exhausts heat at 0°C. What is its percent efficiency?
vampirchik [111]

Answer:

26.8 %

Explanation:

TH = 100°C = 100 + 273 = 373 K

Tc = 0°C = 273 K

The efficiency of the heat engine is given by

\eta = 1-\frac{T_{c}}{T_{H}}

\eta = 1-\frac{273}{373}

η = 0.268

η = 26.8 %

Thus, the efficiency of the heat engine is 26.8 %.

6 0
3 years ago
Suppose that she pushes on the sphere tangent to its surface with a steady force of F = 60 N and that the pressured water provid
sergey [27]

Answer:

25.06s

Explanation:

Remaining part of the question.

(A large stone sphere has a mass of 8200 kg and a radius of 90 cm and floats with nearly zero friction on a thin layer of pressurized water.)

Solution:

F = 60N

r = 90cm = 0.9m

M = 8200kg

Moment of inertia for a sphere (I) = ⅖mr²

I = ⅖ * m * r²

I = ⅖ * 8200 * (0.9)²

I = 0.4 * 8200 * 0.81

I = 2656.8 kgm²

Torque (T) = Iα

but T = Fr

Equating both equations,

Iα = Fr

α = Fr / I

α = (60 * 0.9) / 2656.8

α = 0.020rad/s²

The time it will take her to rotate the sphere,

Θ = w₀t + ½αt²

Angular displacement for one revolution is 2Π rads..

θ = 2π rads

2π = 0 + ½ * 0.02 * t²

(w₀ is equal to zero since sphere is at rest)

2π = ½ * 0.02 * t²

6.284 = 0.01 t²

t² =6.284 / 0.01

t² = 628.4

t = √(628.4)

t = 25.06s

8 0
4 years ago
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