Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 




Upper limit
X when Z has a pvalue of 0.80. So X when 




Answer:
0.125 or 1/8
Step-by-step explanation:
1/4/2
Answer:
1.55%
Step-by-step explanation:
Fill in the values and solve for the rate using the future value formula.
FV = P(1 +r/n)^(nt)
4720 = 4300(1 +r/12)^(12·6)
(4720/4300)^(1/72) = 1 +r/12
r = 12(4720/4300)^(1/72) -1) ≈ 0.015542
The annual interest rate is about 1.55%.
The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours
Answer:
No
Step-by-step explanation:
Do they have common factors?
No which is why they are not able to be simplified further
so no