There are 1.6 5/8's in 1
1.6 is the same as 8/5.
The are 8/5 5/8's in 1
Another way to solve this problem is:
Since we can set it up as:
1/

=8/5
We can also set the problem up as:
5/8*x=1
Then, we can apply the reciprocal rule:
a/b*b/a=1
5/8*8/5=1
The final answer is there are 8/5 5/8's in 1
D is correct
Give me brainliest!! ❤️
Answer:
(a) 0.1414
(b) 0.1010
Step-by-step explanation:
(a)
The density curve is rectangular in shape.
This implies that the distribution of donations is Uniform.
(b)
Compute the probability of donations at least 85 cents as follows:

![=\frac{1}{99}\times [x]^{99}_{85}\\\\=\frac{99-85}{99}\\\\=0.1414\\\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B99%7D%5Ctimes%20%5Bx%5D%5E%7B99%7D_%7B85%7D%5C%5C%5C%5C%3D%5Cfrac%7B99-85%7D%7B99%7D%5C%5C%5C%5C%3D0.1414%5C%5C%5C%5C)
Thus, the proportion of donations that are at least 85 cents is 0.1414.
(b)
Compute the probability of donations between 30 and 40 cents as follows:

![=\frac{1}{99}\times [x]^{40}_{30}\\\\=\frac{40-30}{99}\\\\=0.1010](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B99%7D%5Ctimes%20%5Bx%5D%5E%7B40%7D_%7B30%7D%5C%5C%5C%5C%3D%5Cfrac%7B40-30%7D%7B99%7D%5C%5C%5C%5C%3D0.1010)
Thus, the probability of donations between 30 and 40 cents is 0.1010.
Add the 2s and the 3s together then subtract that by 7