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Luba_88 [7]
3 years ago
12

7 1⁄5 – 6 2⁄5 = ? A. 4⁄5 B. 1 4⁄5 C. 1 1⁄5 D. 13 3⁄5

Mathematics
1 answer:
STatiana [176]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Change the mixed numbers to improper fractions

7 \frac{1}{5} = \frac{36}{5}

6 \frac{2}{5} = \frac{32}{5}

The subtraction is then

\frac{36}{5} - \frac{32}{5}

Both fractions have a common denominator so subtract the numerators leaving the denominator

= \frac{36-32}{5} = \frac{4}{5} → A

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Is the function f(x)=12x3 even or odd? Why?
Umnica [9.8K]

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Step-by-step explanation:

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3 0
3 years ago
14. Solve 10 + 6(-9 – 4x) = 10(x - 12) + 8.
olya-2409 [2.1K]
The answer is c X=_18
5 0
3 years ago
Read 2 more answers
Select all the correct answers. Which two inequalities can be used to find the solution to this absolute value inequality? 3|x +
ziro4ka [17]

The absolute value inequality can be decomposed into two simpler ones.

x < 0

x > -8

<h3></h3><h3>Which two inequalities can be used?</h3>

Here we start with the inequality:

3|x + 4| - 5 < 7

First we need to isolate the absolute value part:

3|x + 4| < 7 + 5

|x + 4| < (7 + 5)/3

|x + 4| < 12/3

|x + 4| < 4

The absolute value inequality can now be decomposed into two simpler ones:

x + 4 < 4

x + 4 > - 4

Solving both of these we get:

x < 4 - 4

x > -4 - 4

x < 0

x > -8

These are the two inequalities.

Learn more about inequalities:

brainly.com/question/24372553

#SPJ1

6 0
1 year ago
Twice the product of 3and a number exceeds the sum of the number and 80 by 10.what is the number?
Hatshy [7]
First, create an equation with the criteria given.

If we let x be your number,
2(3x) = 80 + x + 10
(2(3x) is twice the product of 3 and x, and if it exceeds x+80 by 10, then we add 10 to x+80 to make the two sides of the equation equal.)

Now, solve for x.

6x=90+x \\ 5x=90 \\ x=18

6 0
3 years ago
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