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Lostsunrise [7]
3 years ago
6

PLEASE HELP ME WITH THESE TWO

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

7.

\begin{array}{l|l}{\underline {Statement} &\underline{Reason}\\1.\ MA\ ||\ RY&1.\ \text{Given}\\2.\ \angle M \cong \angle R&2.\ \text{Alternate Interior Angles Theorem}\\3.\ \angle M \cong \angle R&3.\ \text{Given}\\4.\ AY \cong AY&4.\ \text{Reflexive Property}\\5.\ \triangle MAY \cong \triangle RYA&5.\ \text{Angle-Angle-Side Theorem}\\6.\ MY \cong RA&6.\ \text{CPCTC}\\\end{array}


9.

\begin{array}{l|l}{\underline {Statement} &\underline{Reason}\\1.\ \triangle JKM \text{is equilangular}&1.\ \text{Given}\\2.\ \angle J \cong \angle K \cong \angle M&2.\ \text{De-finition of Equiangular}\\3.\ IE \perp MK&3.\ \text{Given}\\4.\ \angle IEK\ \text{and}\ \angle IEM\ \text{are right angles}&4.\ \text{De-finition of Perpendicular}\\5.\ \angle IEK \cong \angle IEM&5.\ \text{Transitive Property}\\6.\ IE \cong IE&6.\ \text{Reflexive Property}\\\end{array}

\begin{array}{l|l}\\7.\ \angle EIK\ \text{and}\ \angle EIM\ \qquad \qquad \qquad \quad &7.\ \text{Triangle Sum Theorem}\\8.\ \angle EIK \cong \angle EIM&8.\ \text{Transitive Property}\\9.\ \triangle IKE \cong \triangle IME&9.\ \text{Angle-Side-Angle Theorem}\end{array}


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You have a coupon for an additional 25% off the price of any sale item at a store. The store has put a watercolor kit on sale fo
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Final price=original price*(100%- discount 1)(100%-discount 2) 
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Answer: $25.5
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3 years ago
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The no-brain way to do it is to

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17) Subtract the right side.

... 10(x +3) -(-9x -4) -(x -5 +3) = 0

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... 18x +36 = 0 . . . . . . . . . . . . . . . . . . . simplified

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_____

If you examine the variable's coefficients you can make a choice of side to subtract that results in a positive coefficient of the variable.

This method puts variable and constant together until the end. The approach usually taught is to separate the variable terms and constant terms. (The number of steps required is the same either way.)

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6 0
3 years ago
Man Street Florist charges
Digiron [165]

Answer:

2 dozens, $41

Step-by-step explanation:

Given data

Man Street Florist charges

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let the number of dozens be x

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2x= 4

x= 4/2

x= 2

Hence the number of dozens is 2

the cost is (put x= 2 in eqn 1 or 2)

y= 20(2)+1

y= 40+1

y= $41

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