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Lostsunrise [7]
3 years ago
6

PLEASE HELP ME WITH THESE TWO

Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

7.

\begin{array}{l|l}{\underline {Statement} &\underline{Reason}\\1.\ MA\ ||\ RY&1.\ \text{Given}\\2.\ \angle M \cong \angle R&2.\ \text{Alternate Interior Angles Theorem}\\3.\ \angle M \cong \angle R&3.\ \text{Given}\\4.\ AY \cong AY&4.\ \text{Reflexive Property}\\5.\ \triangle MAY \cong \triangle RYA&5.\ \text{Angle-Angle-Side Theorem}\\6.\ MY \cong RA&6.\ \text{CPCTC}\\\end{array}


9.

\begin{array}{l|l}{\underline {Statement} &\underline{Reason}\\1.\ \triangle JKM \text{is equilangular}&1.\ \text{Given}\\2.\ \angle J \cong \angle K \cong \angle M&2.\ \text{De-finition of Equiangular}\\3.\ IE \perp MK&3.\ \text{Given}\\4.\ \angle IEK\ \text{and}\ \angle IEM\ \text{are right angles}&4.\ \text{De-finition of Perpendicular}\\5.\ \angle IEK \cong \angle IEM&5.\ \text{Transitive Property}\\6.\ IE \cong IE&6.\ \text{Reflexive Property}\\\end{array}

\begin{array}{l|l}\\7.\ \angle EIK\ \text{and}\ \angle EIM\ \qquad \qquad \qquad \quad &7.\ \text{Triangle Sum Theorem}\\8.\ \angle EIK \cong \angle EIM&8.\ \text{Transitive Property}\\9.\ \triangle IKE \cong \triangle IME&9.\ \text{Angle-Side-Angle Theorem}\end{array}


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Can someone help me with 4 & 5 please :)
svp [43]
Hello there!

4).

125= total
77= constant (stays the same, doesn't change)
8= can change

So our equation will be 125= 77+8h

NOTE: The equal sign is actually a "greater than or equal to" symbol, which isn't a thing on phones lol.

Why? (Equation)

125 is our total. The money that Mrs. Byers pays will be exactly that or less than 125. Basically, it's her budget.

77 is a constant. It's a locked price. It doesn't change. But it's money she has to pay (not her budget). So it goes on the right side.

8h stands for 8 per hour, in this case. (Any letter/variable is fine, but h makes it easier to understand).

Why does 8 have an h? Because for every hour that passes by, Mrs. Byers has to pay 8 more dollars. So it goes on the right with the $77.

I hope this explanation helped! I don't want to solve it for you because I want you to understand WHY the equation is this way. As for solving for the answer, simply solve for h!
---------

Problem 5 is similar to 4. :)

I know these kinds of problems are challenging, and you probably hate them. Don't give up though! With practice and determination, these kinds of problems will be a piece of cake! :) I believe in you, and that you can do this assignment! Best of luck!

-------

DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
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