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sasho [114]
2 years ago
13

Badly needed it now.​

Mathematics
1 answer:
melamori03 [73]2 years ago
3 0

Answer:

1

Step-by-step explanation:

1.litres is the variation statement in the problem.

2.initial volume and distance and final distance is given.

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Another chance for brainliest if it correct ! Please help
frez [133]

Answer:

A B and C are true

Step-by-step explanation:

4 0
3 years ago
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Please help!!!!! it's a word problem and I don't understand how to do it at all
andre [41]
7We can see that line NM = JK so NM also equals 10.
We know NL = 23 and NM = 10 therefore, ML = NL -NM  ML = 23 -13
ML = 10
The last thing to solve is the length of KL
KL = ML / sine 34
KL = 10 / 0.55919
KL = 17.9

Total fence length required = JK + KL + NL =
13 + 17.9 + 23
= 53.9 yards
Cost of Fencing = $3.50 * 53.9 =
<span> <span> <span> $188.65 </span> </span> </span>



8 0
3 years ago
Work out the size of one of the exterior angles
hodyreva [135]

<u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

  • A polygon with 10 sides ( Decagon )

⠀

<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of one of the exterior angles

⠀

<u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\qquad \diamond \:  \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \:  \star

⠀

<u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Putting the given values, we get,

⠀

\sf \dashrightarrow Exterior ~angle =  \dfrac{360  ^\circ}{10} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \frac{36 \cancel{0}^\circ}{ \cancel{10}} \:  \:   \\  \\  \\ \sf \dashrightarrow Exterior ~angle =  \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\  \\

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

\underline{ \rule{227pt}{2pt}} \\  \\

8 0
2 years ago
Read 2 more answers
A television normally sells for $320 this week it’s on sale for 60% off the normal price what is the price of the sale
stira [4]

Answer:

128 dollars

Step-by-step explanation:

You would multiply 60 (that's the percentage off) by 320 ( the price of the T.V) and then subtract the answer you got from multiplying the two from the original price of the T.v (320)

Hope this helps

6 0
3 years ago
Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti
spayn [35]

Answer:

(a)D(x)=-2,500x+60,000

(b)R(x)=60,000x-2500x^2

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500

Therefore, we have:

y=-2500x+b

At point (12,30000)

30000=-2500(12)+b\\b=30000+30000\\b=60000

Therefore:

D(x)=-2,500x+60,000

(b)Revenue

R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0

Therefore:

  • Optimal ticket price:$12
  • Maximum Revenue:$360,000

3 0
3 years ago
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