Answer:
see below
Explanation:
When a substance goes from a solid to a gas without going through a liquid stage . Mothballs is an example.
I'm not quite sure what you are saying. here is an answer to what I think you are saying. in science there are protons (positive) electrons (negative) and neutrons (neutral) I believe the answer is neutron
We can calculate the amount of Oxygen in this volume using the Ideal Gas Equation, PV = nRT, where "P" is the pressure, "V" is the volume, "n" is the number of moles of material, "R" is the gas constant, and "T" is the temperature in Kelvin. To properly answer this problem, all of the information needs to be converted into the proper units. Fortunately, everything except the volume and temperature is in the correct units for the Ideal Gas Equation; the volume can be adjusted by converting mL to L (x1000) and the temperature can be adjusted by adding 273.15 to the current temperature (conversion from Celsius to Kelvin).
Plugging in all the values, we find that:
PV = nRT
(2.7 atm)(0.3 L) = n(0.0821*)(313.15 K)
n = 0.0315 mol Oxygen
Under these conditions, 0.0315 moles of oxygen can be placed in this volume.
Hope this helps!
* - the units are liters times atmospheres divided by moles times Kelvin.
Answer: The correct option is 1.
Explanation: Endothermic reactions are the reactions in which heat is provided to break down the reactant molecules.
In option 1:
The stronger intermolecular forces between the particles in solid molecule are broken down to convert into gaseous form. Hence, some energy in the form of heat is provided to move them far apart. Therefore, it is considered as an endothermic reaction.
In option 2, 3 and 4:
All the other processes involves the formation of bonds and thus there is no need to provide any energy.
Answer:
1 x 10⁻¹¹ M
Explanation:
<u>(Step 1)</u>
Determine the pH.
pH = -log[H⁺]
pH = -log[1 x 10⁻³ M]
pH = 3
<u>(Step 2)</u>
Determine the pOH.
pH + pOH = 14
3 + pOH = 14
pOH = 11
<u>(Step 3)</u>
Determine the hydroxide (OH⁻) concentration.
[OH⁻] = 10^-pOH
[OH⁻] = 10⁻¹¹
[OH⁻] = 1 x 10⁻¹¹ M