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sweet [91]
4 years ago
5

Fossils allow us to analyze how organisms have changed over time. In which type of fossil does the organism get pressured and he

ated and leaves behind an image of what that organism looked like as shown below,
Preserved remains


Carbon film


Mold and cast


Trace fossil
Chemistry
2 answers:
padilas [110]4 years ago
8 0

Answer:

carbon film duh

Mnenie [13.5K]4 years ago
3 0

Answer:

carbon film

Explanation:

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2 years ago
what is the temperature of an 11.2 L sample of carbon monoxide, CO, at 744 torr if it occupies 13.3L at 55 degrees Celsius and 7
Rus_ich [418]

Answer:

3 °C

Explanation:

The pressure is constant, so this looks like a case where we can use Charles’ Law:

\frac{ V_{1} }{T_{1}} = \frac{V_{2} }{T_{2}}  

Invert both sides of the equation.

\frac{T_{1} }{V_{1}} = \frac{T_{2} }{V_{2}}

Multiply both sides by <em>V</em>₂

T_{2} = T_{1} \times \frac{V_{2} }{ V_{1} }

<em>V</em>₁ = 13.3 L; <em>T</em>₁ = (55 + 273.15) K = 328.15 K

<em>V</em>₂ = 11.2 L; <em>T</em>₂ = ?

T_{2} = \text{328.15 K} \times \frac{\text{11.2 L} }{\text{13.3 L}} = \text{276 K} = 3 ^{\circ}\text{C}

8 0
3 years ago
Calculate the equilibrium constant, k, at 25°c for the galvanic cell reaction shown below: 8 h+(aq) + 5 fe2+(aq) + mno4-(aq) → m
Mashcka [7]

Answer:

Equilibrium Constant = (3.60 × 10⁶²)

Explanation:

The change in Gibb's free energy for a galvanic cell is given as

Δ = -nFE°

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But the change in Gibb's free energy for galvanic cell reaction is also given as

ΔG = -RT In K

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T = absolute temperature in Kelvin = 25 + 273.15 = 298.15 K

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Equating these two expressions

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RT In K = nFE°

In K = (nFE°) ÷ (RT)

In K = (5 × 96500 × 0.74) ÷ (8.314 × 298.15)

In K = 144.04

K = e^(144.04)

K = (3.60 × 10⁶²)

Hope this Helps!!!

5 0
4 years ago
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lesantik [10]
<span>Cadmium Permanganate

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