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Marizza181 [45]
3 years ago
10

Which of the following statements is true about aquaculture? A. An aquaculturist can throw some young shrimp in a pond, and they

will take care of themselves. B. Aquaculture means "cultivating small acreages of land." C. An aquaculturist must tend to the tanks carefully to make sure predators do not eat the shrimp. D. The tanks are large aquariums built in warehouses.
Chemistry
1 answer:
Delvig [45]3 years ago
8 0

B. Aquaculture means "cultivating small acreages of land."

Explanation:

Aquaculture is the growing of fishes, crustaceans, molluscs, oysters and other marine organisms like algae in a small acreage of farm. Normally, the carryign capacity per acreage would be lower in the natural habitat – like in the oceans- but this is raised substantially in aquaculture due to adopting certain farming techniques. An example is by cycling the wastewater from teh fish tanks to plants that take up the waste as nutrients and oxygenate the water, The water is then recycled back to the tanks as cleaner water reusable by the fishes and teh cycle continues. This cycle ensures the sustainability of the farm even with very little water compared to the natural environment.  

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Express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms
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Answer:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]

B = b -a/RT

C = b^2

a = 1.263 atm*L^2/mol^2

b = 0.03464 L/mol

Explanation:

In the given question, we need to express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms of the parameters a and b. Therefore:

Using the van deer Waals equation of state:

P = \frac{RT}{V_{m}-b } - \frac{a}{V_{m} ^{2} }

With further simplification, we have:

P = RT[\frac{1}{V_{m}-b } - \frac{a}{RTV_{m} ^{2} }]

Then, we have:

P = \frac{RT}{V_{m} } [\frac{1}{1-\frac{b}{V_{m} } } - \frac{a}{RTV_{m} }]

Therefore,

PV_{m} = RT[(1-\frac{b}{V_{m} }) ^{-1} - \frac{a}{RTV_{m} }]

Using the expansion:

(1-x)^{-1} = 1 + x + x^{2} + ....

Therefore,

PV_{m} = RT[1+\frac{b}{V_{m} }+\frac{b^{2} }{V_{m} ^{2} } + ... -\frac{a}{RTV_{m} }]

Thus:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]           equation (1)

Using the virial equation of state:

P = RT[\frac{1}{V_{m} }+ \frac{B}{V_{m} ^{2}}+\frac{C}{V_{m} ^{3} }+ ...]

Thus:

PV_{m} = RT[1+ \frac{B}{V_{m} }+ \frac{C}{V_{m} ^{2} } + ...]     equation (2)

Comparing equations (1) and (2), we have:

B = b -a/RT

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Using the measurements on argon gave B = −21.7 cm3 mol−1 and C = 1200 cm6 mol−2 for the virial coefficients at 273 K.

b = \sqrt{C} = \sqrt{1200} = 34.64[tex]cm^{3}/mol[/tex] = 0.03464 L/mol

a = (b-B)*RT = (34.64+21.7)*(1L/1000cm^3)*(0.0821)*(273) = 1.263 atm*L^2/mol^2

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