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VMariaS [17]
3 years ago
5

During an experiment a scientist observed prokaryotes that lived near volcanic vents deep in the ocean the scientist most likely

observed
A. Photoautotrophs
B. Chemoautotrophs
C. Heterotrophs
D. Photoheterotrophs
Biology
2 answers:
Natalija [7]3 years ago
4 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The correct answer is B. Chemoautotrophs.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

Leona [35]3 years ago
3 0
The correct awnser is b .............................
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If Mr. Lynch wanted to find out how well a new type of fertilizer worked on his Avocado trees, how
sashaice [31]

Answer:

you would use two trees and watch them for a specific amount of time(a month or two). measure them each day to see how much they grow.One tree with the fertilizer and one without

8 0
4 years ago
In response to action potentials arriving fiom the transverse tubules, the surcoplasmic reticulum releases
sveta [45]

Answer:

D. Calcium ions.

Explanation:

Here we are talking about the mechanism of muscle contraction. The most accepted theory of muscle contraction is sliding filament theory. It was given by Huxley and Huxley. During the process actin filaments slides over myosin filament by forming cross bridges. The sequence of events are as follows:

a. An action potential propagates through the motor nerve and reach the nerve endings on the muscle fiber at neuro-muscular junction.

b. Neurotransmitter called acetylcholine is released by the nerve endings.

c. Acetylcholine binds to the receptors on muscle fiber and opens the gated channels which causes flow of Na+ ions into the muscle fiber.

d. This influx of sodium ions initiates an action potential in the muscle fiber which reaches the T- tubules or transverse tubules. Here it causes the sarcoplasmic reticulum to release large amounts of calcium ion.

e. Calcium ions are responsible for initiating the attractive forces between actin and myosin filaments. Cross bridges are formed, actin slides over myosin causing the contraction of muscle.

3 0
4 years ago
Match each metamorphic rock with the correct parent rock. 1. quartzite limestone 2. marble sandstone 3. slate shale
vladimir1956 [14]

<u>Answer</u>:

  1. Quartzite - sandstone
  2. Marble - limestone
  3. Slate - shale

<u>Explanation</u>:

  • <em>Metamorphic</em> rocks are named after the term metamorphism, which means 'to change'. These rocks are called so because they change from one form to another due to several external factors.
  • <em>Parent rocks</em> are the original rocks from which the metamorphic rocks are formed after undergoing changes.
  • Sandstone, limestone, and shale are all sedimentary rocks which change their form due to high heat, pressure, temperature, and chemical activity and form their respective metamorphic rocks.
  • Thus, <em>sandstone, limestone, and shale are parent rocks and quartzite, marble and slate are the respective metamorphic rocks formed from them.</em>



5 0
4 years ago
Read 2 more answers
uppose that molecules of glucose are ingested, absorbed into the bloodstream, and then converted inside muscle cells to carbon d
Sophie [7]

Answer:

Phase 1: Preparation, regulation and energy expenditure

In the initial preparatory phase of glycolysis (investment phase), glucose is phosphorylated twice by ATP and cleaved into two phosphate trioses. [2] At this stage, the cell spends two molecules of ATP, the Mg2 + cation is indispensable for the reactions, and five biochemical reactions are processed. No energy is stored, on the contrary, two ATP molecules are invested in phosphorylation reactions.

Reaction 1: hexokinase

In the first reaction, the glucose entering the tissues is phosphorylated to the hydroxyl group at C6, with the energy expenditure of an ATP molecule, giving rise to glucose-6-phosphate and ADP. [1] This reaction, catalyzed by the hexokinase enzyme, is irreversible under physiological conditions due to its highly negative ΔG °. It is one of the three steps that regulate glycolysis. The phosphorylation of glucose in the first reaction prevents it from leaving the cell again (glycolysis takes place in the cell's cytosol). By adding a phosphate group to glucose, it becomes a negatively charged molecule and it is impossible to passively pass through the cell membrane, keeping it trapped within the cell.

Glucose-6-phosphate is a branching point in carbohydrate metabolism. It is a precursor to almost all routes that use glucose, including glycolysis, via pentose phosphate and glycogen synthesis. From an opposite point of view, it can also be generated from other carbohydrate metabolism routes, such as glycogenolysis (glycogen breakdown), via pentose phosphate and gluconeogenesis (synthesis of glucose from non-carbohydrates).

Hexokinases, enzymes that catalyze glucose phosphorylation, are a family of tissue-specific isoenzymes that differ in their kinetic properties. The isoenzyme found in the liver and cells of the pancreas has a much higher Km than other hexokinases and is called glycokinase. Kinases are enzymes that catalyze the transfer of a terminal phosphoryl group from ATP to a nucleophile acceptor. In the case of hexokinase, the acceptor is a hexose, usually D-glucose, although hexokinase can catalyze the phosphorylation of other common hexoses, such as D-fructose and D-mannose. Hexokinase, like many other kinases, requires Mg2 + for its activity, since the true substrate of the enzyme is not ATP-4, but MgATP-2. In many cells, part of the hexokinase is bound to porins in the outer mitochondrial membrane, which give these enzymes early access to the newly synthesized ATP as it leaves the mitochondria.

Reaction 2: phosphohexose isomerase

In the second reaction, catalyzed by the enzyme glycosphosphate isomerase (also called phosphoxose isomerase), glucose-6-phosphate, an aldose, is converted into a reversible isomerization process in fructose-6-phosphate, a ketosis, thus allowing a site input for dietary fructose in glycolysis. This isomerization plays a critical role in the general chemistry of the glycolytic pathway, since the rearrangement of the carbonyl and hydroxyl groups at C-1 and C-2 is a necessary preparation for the next two steps. The phosphorylation that occurs in the next reaction (reaction 3) requires that the group at C-1 be first converted from a carbonyl to an alcohol and, in the subsequent reaction (reaction 4), the cleavage of the bridge between C-3 and C-4 by aldolase requires a carbonyl group at C-2.

Reaction 3: phosphofructokinase-1 (PFK1)

In reaction number 3, the cell invests another ATP molecule to phosphorylate fructose-6-phosphate and convert it to fructose-1,6-bisphosphate. This is also an irreversible and control reaction of this metabolic pathway, catalyzed by the enzyme phosphofrutokinase, which is the enzyme pacemaker of glycolysis. This step occurs to make the molecule symmetrical for the cleavage reaction in the next step.

Reaction 4: aldolase

In reaction 4, fructose-1,6-bisphosphate is cleaved into two trioses: glyceraldehyde-3-phosphate and dihydroxyacetone phosphate. This reaction is catalyzed by the enzyme aldolase.

Reaction 5: triosphosphate isomerase

Glyceraldehyde-3-phosphate and dihydroxyacetone phosphate are isomers that are easily interconnected by the enzyme triosphosphate isomerase. Then, the conversion of dihydroxy ketone P into glyceraldehyde 3P occurs, the only triosis that can continue to be oxidized.

Phase 2: ATP production and oxidation

In the ATP generation phase (yield), glyceraldehyde-3-phosphate (a phosphate triosis) is oxidized by NAD and phosphorylated using inorganic phosphate. The high-energy phosphate bridge generated in this step is transferred to the ADP to form ATP. The remaining phosphate is also rearranged to form another high-energy phosphate bridge that is transferred to the ADP. As there are two moles of phosphate triosis formed, the result

Explanation:

5 0
3 years ago
Seismologist calculate the difference in the arrival times P waves
Ghella [55]
Edit. Answer - Depending on the waves they must measure both at the same station in order to calculate and have knowledge of the interior of the earth. Reasoning - S waves are sheer waves where as P waves are compressional which leads to both factors of understanding the strength and changes going on in the earth.
4 0
4 years ago
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