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Salsk061 [2.6K]
3 years ago
12

If a man with one dominant gene for Huntington’s disease marries a women who has no genes for the disease, what is the probabili

ty that their child will have the disease?
a. 25%
b. 100%
c. 0%
d. 50%
Biology
1 answer:
Westkost [7]3 years ago
3 0

Answer:

The correct answer is 50 %.

Explanation:

Huntington’s disease has autosomal dominant inheritance. This means that the children of one parent with one dominant gene for Huntington’s disease will get the disease with a 50% chance.

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