PLEASE HELP ALSO WILL GET THE BRAINIEST ANSWER!!!! ALSO SHOW YOUR WORK!!!!

2 answers:

6 0

I=PRT
I=Interest
P=principal
R=rate in decimal
T=time in years

1year=12months
72months/12months=6 years
t=6

given
I=8925
P=35000
R=r
T=6

8925=35000*r*6
8925=210000*r
divide both sides by 210000
0.0425=r

the interest rate is 4.25%

Neporo4naja [7]2 years ago

6 0

We know, Interest rate = P * R * T / 100

Here, Interest (I) = 8925
Principle rate (P) = 35,000
Time (T) = 72 months = 72/12 = 6 years
Rate (R) = ?

Substitute their values into the expression:
8925 = 35000 * R * 6 / 100
R = 8925 * 100 / 35000 * 6
R = 892500 / 210000
R = 4.25%

In short, Your Final Answer would be 4.25%

Hope this helps!

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A fair coin is tossed repeatedly with results Y0, Y1, Y2, . . . that are 0 or 1 with probability 1/2 each. For n ≥ 1 let Xn = Yn

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Answer:

False. See te explanation an counter example below.

Step-by-step explanation:

For this case we need to find:

$P(X_{n+1} = | X_n =i, X_{n-1}=i') =P(X_{n+1}=j |X_n =i)$ for all $i,i',j$ and for $X_n$ in the Markov Chain assumed. If we proof this then we have a Markov Chain

For example if we assume that $j=2, i=1, i'=0$ then we have this:

$P(X_{n+1} = | X_n =i, X_{n-1}=i') =\frac{1}{2}$

Because we can only have $j=2, i=1, i'=0$ if we have this:

$Y_{n+1}=1 , Y_n= 1, Y_{n-1}=0, Y_{n-2}=0$ , from definition given $X_n = Y_n + Y_{n-1}$

With $i=1, i'=0$ we have that $Y_n =1 , Y_{n-1}=0, Y_{n-2}=0$

So based on these conditions $Y_{n+1}$ would be 1 with probability 1/2 from the definition.

If we find a counter example when the probability is not satisfied we can proof that we don't have a Markov Chain.

Let's assume that $j=2, i=1, i'=2$ for this case in order to satisfy the definition then $Y_n =0, Y_{n-1}=1, Y_{n-2}=1$

But on this case that means $X_{n+1}\neq 2$ and on this case the probability $P(X_{n+1}=j| X_n =i, X_{n-1}=i')= 0$ , so we have a counter example and we have that:

$P(X_{n+1} =j| X_n =i, X_{n-1}=i') \neq P(X_{n+1} =j | X_n =i)$ for all $i,i', j$ so then we can conclude that we don't have a Markov chain for this case.