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NISA [10]
4 years ago
5

Help Plez 20 Points Due Today

Mathematics
2 answers:
Jobisdone [24]4 years ago
8 0

Answer:6.25

Step-by-step explanation :  ratio of areas = one half :two point five in a half        

=1.0:6.25

7nadin3 [17]4 years ago
3 0

Answer:

A

Step-by-step explanation:

You might be interested in
There are six households in a rural community. Each household earns $40,000 per year. Suppose that a new resident builds a mansi
dusya [7]

Answer:

Median income has not changed

Mean income has increased

Step-by-step explanation:

Initial number of houses = 6

Earning per household = $40,000

The initial mean :

$(40,000 * 6) / 6 = $40000

Initial median :

40000, 40000, 40000, 40000, 40000, 40000

= 1/2(n+1)th term,

Median = 40000

A 7th household earns 4,000,000

Mean = ((40000*6) + 4,000,000) / 7 = $605,714

Median = 1/2(n+1)th term

40000, 40000, 40000, 40000, 40000, 40000, 4000000

Median = 4th term = 40000

7 0
3 years ago
2(x + 2) = 3x = 2(x + 1) + 1
Karo-lina-s [1.5K]
2 it’s two says the calculator
7 0
4 years ago
Read 2 more answers
Simplify 5p2 over 5p3
castortr0y [4]

Answer:

1/p^1

Step-by-step explanation:

5p^2/5p^3

  1. cancel the fives
  • p^2/p^3

2. subtract denominator exponent from numerator exponent

  • p^-1
  • (you can't have negative exponents so you have to move the negative exponent coefficient to the denominator to make it possitive)

3. 1/p^1

4 0
3 years ago
Can anyone help with this asap?<br>8x² + 26xy + 15y²​
Ainat [17]

Answer:

x =  − 13 y ± 7 y / 8

Step-by-step explanation:

4 0
3 years ago
Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac
melomori [17]
Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ b+c=20
Equation [2] ⇒ 1.50b+5c=54.50

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; b and c, that we need to solve, then this becomes a simultaneous equation problem. 

First, rearrange Equation [1] to make either b or c the subject:
b+c=20
b=20-c

Then we substitute b=20-c into Equation [2]
1.50b+5c=54.50
1.50(20-c)+5c=54.50
30-1.50c+5c=54.50
5c-1.5c=54.50-30
3.5c=24.50
c=7

Now we know the value of c which is c=7, substitute this value into b=20-c we have b=20-7=13

Answer:
Numbers of books = 13
Numbers of CDs = 7
5 0
4 years ago
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