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3 years ago

How can you tell which end of a worm is his head

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

7 0

They have a band around them close to the ‘front end, ' sorry if this doesn't help, lol. :)

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In un trapezio rettangolo la base minore, il lato obliquo e l'altezza misurano rispettivamente 60 cm. 95 cm è 76 cm. Calcola il

KengaRu [80]

Answer:

$2p=348 cm\: S=6726 cm^{2}$

Step-by-step explanation:

Ciao, come stai?

1) Per prima cosa, dobbiamo trovare la misura della base più grande. Scomponendo la figura possiamo visualizzare un triangolo e un quadrato. Ci sono somiglianze con gli angoli. Quindi è un triangolo rettangolo. Applichiamo il teorema di Pitagora:

$a^2=b^2+c^2\\95^2=b^2+76^2\\57=b$

2) Perimetro:

$2p=60+57+76+60+95\\2p=348 cm$

3) L' area

$\frac{(B+b)h}{2} =\frac{(117+60)76}{2} =6726 \:cm^{2}$

8 0

3 years ago

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago

There are 3 red pens, 4 blue pens, 2 Blac pens, and 5 green pens in drawer, suppose you choose a pen at random

Alenkasestr [34]

Answer:

1. 3/14

2. 2/7

3. 1/7

4. 5/14

5. 11/14

6. 9/14

Step-by-step explanation:

first get the total number of pens

3 red pens + 4 blue pens + 2 black pens + 5 green pens =

14 total number of pens

1. What is the probability that the pen chosen red?

3 red pens out of a total of 14 pens = 3/14

2. What is the probability that the pen chosen is blue?

4 blue pens out of a total of 14 pens = 4/14 -> simplified -> 2/7

3. What is the probability that the pen chosen is black?

2 black pens out of a total of 14 pens = 2/14 -> simplified -> 1/7

4. What is the probability that the pen chosen is green?

5 green pens out of a total of 14 pens = 5/14

5. What is the probability that the pen chosen is NOT red?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

4 blue pens, 2 black pens and 5 green pens are NOT red

4 blue pens + 2 black pens + 5 green pens =

11 total number of pens that are NOT red

11 total number of pens that are NOT red out of a total of 14 pens = 11/14

6. What is the probability that the pen chosen is NOT green?

of the 3 red pens, 4 blue pens, 2 black pens and 5 green pens

the 3 red pens, 4 blue pens, 2 black pens are NOT green

3 red pens + 4 blue pens + 2 black pens =

9 total number of pens that are NOT green

9 total number of pens that are NOT green out of a total of 14 pens = 9/14

gathmath.com

6 0

1 year ago

Read 2 more answers

J is 14 less than 22 as an equation<br> with what j=

Olegator [25]

22 - 14 = 8

so i think j = 8

4 0

2 years ago

Please Help. I’m confused. I will give Brainliest Answer.

RUDIKE [14]

Answer:

Step-by-step explanation:

The other situations do not represent a 60% probability.

B is a situation in which 40% of people prefer aisle seats.

C is a situation in which 33% of people prefer aisle seats

D is a situation in which 66% of people prefer aisle seats.

3 0

3 years ago