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Kruka [31]
3 years ago
13

Indentify the radical expression

^{1/4} " alt=" 6{}^{1/4} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Tamiku [17]3 years ago
8 0

Answer:

D. 4th root of 6

Step-by-step explanation:

6^(1/4) = 4th root of 6^1 = 4th root of 6

Answer is D. 4th root of 6

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Chris ran 25 miles, while Bill ran 5 miles. How many times farther did Chris run than Bill?
mixer [17]

Answer: Chris ran 20 miles more then Bill

Step-by-step explanation:

25(Chris) - 5(Bill) = 20 Miles

Hope this helped, have a great day/night!

~IFoundJiminsLostJams~

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3 years ago
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If item costs $99.99 with 15% off and I get final price. It then asks me what percentage of savings. How do I get the percentage
nirvana33 [79]
Ok.. if you got 84.99 as you answer then you would put .15 *99.99 then you would get 14.9985 then round and get 15.00 and then 99.99 - 15.00 ....you will get 84.99...i think
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What is the best name for angle Y?
stepan [7]
The answer to the question is B
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3 years ago
Determine any asymptotes (Horizontal, vertical or oblique). Find holes, intercepts and state it's domain.
vesna_86 [32]

Factorize the denominator:

\dfrac{x^2-4}{x^3+x^2-4x-4}=\dfrac{x^2-4}{x^2(x+1)-4(x+1)}=\dfrac{x^2-4}{(x^2-4)(x+1)}

If x\neq\pm2, we can cancel the factors of x^2-4, which makes x=-2 and x=2 removable discontinuities that appear as holes in the plot of g(x).

We're then left with

\dfrac1{x+1}

which is undefined when x=-1, so this is the site of a vertical asymptote.

As x gets arbitrarily large in magnitude, we find

\displaystyle\lim_{x\to-\infty}g(x)=\lim_{x\to+\infty}g(x)=0

since the degree of the denominator (3) is greater than the degree of the numerator (2). So y=0 is a horizontal asymptote.

Intercepts occur where g(x)=0 (x-intercepts) and the value of g(x) when x=0 (y-intercept). There are no x-intercepts because \dfrac1{x+1} is never 0. On the other hand,

g(0)=\dfrac{0-4}{0+0-0-4}=1

so there is one y-intercept at (0, 1).

The domain of g(x) is the set of values that x can take on for which g(x) exists. We've already shown that x can't be -2, 2, or -1, so the domain is the set

\{x\in\mathbb R\mid x\neq-2,x\neq-1,x\neq2\}

8 0
3 years ago
she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, wh
yKpoI14uk [10]

Answer:     \dfrac{1}{2}

Step-by-step explanation:

We know that probability for any event = \dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3=  12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}

Hence, the  probability that it will be cherry is \dfrac{1}{2} .

7 0
3 years ago
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