Answer:
The answer is "new version of application provides more easy to use".
Explanation:
- In computer science, an application is a program, that is installed on the computer. There are many types of application software, that are "gaming software, working software, programming software, etc." At the end of time users want some new things in software to know users need programmer developed new versions of the software.
- The update usually improves the device or service in its current version, whilst an improvement is an entirely new version. Installation is usually free and easy. You also have to wait for updates that are difficult to install.
<span>Loads of ‘easy to use’ programmes and ‘How To’ guides make it simple for anyone to put a brochure/newsletter/marketing piece together – how difficult can it be with so much help available? Technology has not only changed the way designs are accomplished, it’s changed the perception of ‘design’ from a hard earned skill to something you can learn in an afternoon off.
via </span>https://dmjcomputerservices.com/blog/technology-changed-design-industry/
The Internet Simulator is a tool developed by Code.org for our new high school Computer Science Principles class. ... The Internet Simulator was designed to be used in a classroom with students working collaboratively in-person to solve problems.
Answer:
x^2 * b^2
Explanation:
Like 3 squared times 2 squared is 3*3*2*2. Similarly the expression given in the question is equal to x*x*b*b. And that explains what is mentioned in question.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
