Answer:
a. 6 bits
b. 1
Explanation:
Ans (a)
40 Characters need to be represent by binary coded Zebronian (BCZ) , So You will need 6 bits.
5 bits wold only give you 32 = 2 x 2 x 2 x 2 x 2 unique characters.
So 6 bits would allow you to represent 64 characters.
Ans(b)
BCD = Binrary Coded Decimal is very common in electronics, particularly it displays numerical data.
BCD Encodes each digit of a decimal number into 4 digit binary form.
Each decimal digit is indiviidually converted to oits binary equivalent
For Example : 146 , the decimal degits are replaced by 0001 , 0100 and 0110 respectively
Addition
1 0 = 10 is binary value of 2 2
+1 1 = 11 is binary value of 3 + 3
---------- -----------
1 0 1 5 Ans
Subtraction
1 1= binary value of 3 3
- 1 0 = binary value of 2 - 2
--------- -----------
0 1 1 Ans
Answer:
It’s Java script I think and it makes something say hello everybody
Explanation:
Answer:
def rec_dig_sum( num ):
num_list = [ digit for digit in str(num)]
total = 0
for x in num_list:
total += x
return total
def dict_of_rec_dig_sums(low, high):
mydict = dict()
for number in the range(low, high+1):
mydict[rec_dig_sum(number)] = number
return mydict
Explanation:
The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.
The program returns a dictionary with the recursive sum as the keys and the number count as the values.
Answer:
Follows are the solution to this question:
Explanation:
The process ID is not static because this can't be used to identity, therefore, it includes excellent service providers like HTTP since it is allocated dynamically only to process whenever a process is initiated.
Sometimes its instance connectors are managed on numerous TSAPs. This can be implemented unless the process ID is being used as each procedure could have an identity.
Answer:
4000k-ohm to 10,000k-ohm
Explanation:
As we know that time constant for an RC circuit is t=RC
Putting the values of t we can get the range of varaiable resistor as;
t=RC
Putting t=2 we get the first value of the range for the variable resistor
2=R*0.500*10^-6
R=2/(0.500*10^-6)
R=4*10^6
R=4000k-ohm
Now putting t=5 we get the final value for the range of variable resistor
t=RC
5=R*0.500*10^-6
R=5/(0.500*10^-6)
R=10*10^6
R=10,000k-ohm
So variable resistance must be made to vary in the range from 4000k-ohm to 10,000k-ohm
