All categories

3 years ago

Ok now that the image works did I do this right?

Mathematics

1 answer:

Arturiano [62]3 years ago

7 0

Yess!! That’s how u do it && continue to work hard!

You might be interested in

Which point on the graph could represent the ratio of 2 white flowers for every 3 pink flowers that will be in one row of Molly’

vekshin1

Answer: It’s B

Step-by-step explanation:

I just did the quiz

7 0

3 years ago

A parking garage charges $4.50 for each hour you park. You have $18 in your pocket.

Eva8 [605]

Answer:

4 hours

Step-by-step explanation:

set up your equation

money to spend = charge per hour

18 = 4.50x

divide each side by 4.50

x = 4

4 hours

3 0

3 years ago

Read 2 more answers

Math Help? 15 Points

devlian [24]

Umm. Is this high school?.
4 friends x 2 ballons = 8 friends only ballons.
8 + 1 = 9.
9 total

4 0

3 years ago

5m - 4n, when m=5 and n = 3.

tiny-mole [99]

Answer:

5m - 4n

5(5) - 4(3) ( As m= 5 and n= 3)

25 - 12

= 13

8 0

2 years ago

Read 2 more answers

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago