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LenKa [72]
3 years ago
7

Ok now that the image works did I do this right?

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0
Yess!! That’s how u do it && continue to work hard!
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Do these ratios form a proportion? 26 medium hats to 2 small hats 39 medium hats to 3 small hats
inessss [21]

\bf \cfrac{\textit{medium hats}}{\textit{small hats}}\qquad \qquad \cfrac{26}{2}=\cfrac{39}{13}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=\cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 13}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 13= 13~~\textit{\Large \checkmark}

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3 years ago
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If (x - 4) varies inversely as (y + 3) and x = 8 when y = 2, what is x when y = - 1?
denpristay [2]

Answer:

x=14

Step-by-step explanation:

If two values are inversely proportional, their product must be maintained. That way, if one value goes up, the other goes down by the same extent.

Therefore, if (x-4) and (y+3) vary inversely, their product will be the same for all values of x-4 and y+3.

Let x=8 and y=2 as given in the problem. Substitute values:

(8-4)(2+3)=(4)(5)=20

Hence, the maintained product is 20.

Thus, we have the following equation:

(x-4)(y+3)=20

Substitute y=-1 to find the value of x when y=-1:

(x-4)(-1+3)=20,\\(x-4)(2)=20,\\x-4=10,\\x=10+4=\boxed{14}

3 0
2 years ago
How would you factor a quadratic expression like 9x^2-4
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Hello, we need to see it as a difference of two squares as we know that for all a and b real numbers

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So, here

9x^2-4=(3x)^2-2^2=(3x-2)(3x+2)

Voila !

Thank you

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Step-by-step explanation:

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