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melomori [17]
3 years ago
13

A farmer who has fixed amounts of land and capital finds that total product is 24 for the first worker hired, 32 when two worker

s are hired, 37 when three are hired, and 40 when four are hired. The farmer's product sells for $3 per unit, and the wage rate is $13 per worker. The marginal product of the second worker is
A. 8.
B. 1.
C. 24.
D. 5
Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer:

A. 8.

Step-by-step explanation:

The marginal product is the increase in output (units produced) resulting from employing one more worker. Therefore, the marginal product of the second worker (M2) is given by the difference between the total product with two workers and the total product with one worker.

M_2 =32-24\\M_2 =8

The answer is A. 8.

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A grid model with 100 squares. 73 squares are shaded. What percent of the model is shaded? What is the equivalent ratio? What is
viva [34]

Answer:

73%

Step-by-step explanation:

First, you'll divide the total squares by 100 to get how much is one percent. Then, you divide the shaded squares by the value of 1%. And you'll get how many percents are shaded.

For equivalent decimal, you divide the number by 100.

Then for equivalent decimal, you get the percent and 100.

p =100/100=1\\73/1=73\\=0.73\\=\frac{73}{100}

5 0
3 years ago
Help me please......!!!!
8090 [49]

Answer: B

Step-by-step explanation:

The range of a function is the set of all possible values for the function's dependent variable. In this case, that variable is y, so we can look at the graph to observe what possible y-values fit in the range.

There are no y-values below -1 on the chart, and the function goes upwards to infinity, so the correct answer is B, y is greater than or equal to -1.

5 0
3 years ago
the perimeter of a triangle is 12cm. which one of the following is not possible sides of a trianglr? a)1 b)5 c)6 d)none of thish
Phantasy [73]

Perimeter of triangle = 3(side)

P = 3(s)

12 = 3s

12/3 = s

4 = s

I think there is a typo in your post.

The question should be: WHICH ONE OF THE FOLLOWING IS A POSSIBLE SIDE OF THE TRIANGLE?

In that case, 4 cm is the answer. However, 4 cm is not listed among the choices. So, choice d is the answer.

7 0
4 years ago
Line Q is represented by the following equation: 2x + y = 11 Which equation completes the system that is satisfied by the soluti
inna [77]
X + Y= 8
If you plug the value (3, 5) for x and y, you will arrive at your destination (answer).
X=3
Y=5
3 + 5 = 8
6 0
3 years ago
Read 2 more answers
ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
<span>
3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
<span>
4. W</span>rite the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:<span>

</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
<span>
Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

6 0
3 years ago
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