Question

The given line passes through the points (0, -3) and (2, 3).

Answer 1

Answer:

The answer is: y+1=(3x+1)

Step-by-step explanation:

Answer 2

Answer:

$y+1=3(x+1)$

Step-by-step explanation:

Ok so we are looking for line parallel to the line containing points (0,-3) and (2,3).

Parallel lines have the same slope.

So let's find the slope of the line containing the points (0,-3) and (2,3).

You can use the formula $m=\frac{y_2-y_1}{x_2-x_1}$.

However, I just like to line up the points vertically and subtract them vertically, then put 2nd difference over 1st difference. Like this:

(0 , -3)

-(2 ,  3)

-----------

-2     -6

So the slope is -6/-2 or just 3.

So the slope of the line we are looking for has slope 3 (or m=3) and your line should contain the point (-1,-1).

The point slope form of a line is:

$y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point you know on the line.

So we just plug into that equation now.  That gives us:

$y-(-1)=3(x-(-1))$

Simplify a bit:

$y+1=3(x+1)$