Answer:
The length for the 97th percentile for a man's arm span is 74.96 inches.
Step-by-step explanation:
We have a normal distribution for men's arm span, with mean of 68 inches and standard deviation of 3.7 inches.
The 97th percentil represents the value for which 97% of the observations are below.
We can search for the 97th percentile for the standard normal distribution. This will give a value z=1.88.
Then, we can convert this z-score to our distribution:
