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const2013 [10]
3 years ago
9

How do I solve “csc 30° =”

Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

"Csc" is an abbreviation for cosecant, which is the reciprocal of sine.

Sine = o/h

Cosecant = h/o

In this case, the value of cosecant 30 degrees is equal to 2.


grigory [225]3 years ago
7 0

Answer:

csc 30 =2

Step-by-step explanation:

sin 30 - 1/2

csc 30= 1/sin 30=1: (1/2)=2

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In a study of 200 students under 25 years old, 20% have not yet learned to drive. How many students cannot drive? Show me your w
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200 students under 25

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Sample spaces For each of the following, list the sample space and tell whether you think the events are equally likely:
Schach [20]

Answer and explanation:

To find : List the sample space and tell whether you think the events are equally likely ?

Solution :

a) Toss 2 coins; record the order of heads and tails.

Let H is getting head and t is getting tail.

When two coins are tossed the sample space is {HH,HT,TH,TT}.

Total number of outcome = 4

As the outcome HT is different from TH. Each outcome is unique.

Events are equally likely since their probabilities \frac{1}{4} are same.

b) A family has 3 children; record the number of boys.

Let B denote boy and G denote girl.

If there are 3 children then the sample space is

{GGG,GGB,GBG,BGG,BBG,GBB,BGB,BBB}

The possible number of boys are 0,1,2 and 3.

Number of boys      Favorable outcome    Probability

           0                      GGG                        \frac{1}{8}

           1                    GGB,GBG,BGG          \frac{3}{8}

           2                   GBB,BGB,BBG           \frac{3}{8}

           3                       BBB                         \frac{1}{8}

Since the probabilities are not equal the events are not equally likely.

c)  Flip a coin until you get a head or 3 consecutive tails; record each flip.

Getting a head in a trial is dependent on the previous toss.

Similarly getting 3 consecutive tails also dependent on previous toss.

Hence, the probabilities cannot be equal and events cannot be equally likely.

d) Roll two dice; record the larger number

The sample space of rolling two dice is

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now we form a table that the number of time each number occurs as maximum number then we find probability,

Highest number        Number of times         Probability

           1                                   1                     \frac{1}{36}

           2                                  3                    \frac{3}{36}

           3                                  5                    \frac{5}{36}

           4                                  7                    \frac{7}{36}

           5                                  9                    \frac{9}{36}

           6                                  11                    \frac{11}{36}

Since the probabilities are not the same the events are not equally likely.

4 0
3 years ago
HELP ASAP PLEASE HELP NOW
kow [346]

Answer:

the 2nd option f(-4) = g(-4) and f(0) = g(0)

Step-by-step explanation:

the right answer was the same x and sampe y. it means in their intersection for both f(x) anad g(x)

so the correct answer is f(0) = g(0) and f(-4) = g(-4)

4 0
2 years ago
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