Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Answer:
![[tex] {6x}^{2} + 4xy - 3x - 2y](https://tex.z-dn.net/?f=%5Btex%5D%20%7B6x%7D%5E%7B2%7D%20%2B%204xy%20-%203x%20-%202y)
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6x²+4xy-3x-2y
2x(3x+2y)-1(3x+2y)
(3x+2y)(2x-1) is your answer
Answer:
6 inches
Step-by-step explanation:
For an edge length of s, the six square faces of the cube add to an area of ...
cube area = 6s²
Filling in the given information and solving for s, we get
216 = 6s²
36 = s² . . . . . divide by 6
√36 = s = 6 . . . . take the square root
The edge length is 6 inches.
Answer:
B
Step-by-step explanation:
