The perimeter of a square is 12cm what is its length of its size?

2 answers:

6 0

If the perimeter of a square is 12cm and you are looking for the length of one side. You divide 12cm by 4 because it is a square and you get 3cm for one of the lengths of the side.

liraira [26]3 years ago

5 0

A square has 4 sides.

If the perimeter around the square is 12cm, then you do 12 ÷ 4, which is 3.

Each side is 3cm long.

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Ok So I an taking algebra 1 and this question is really confusing me.

V125BC [204]

You use the arithmetic sequence formula and input the information given to you.
tn = a + (n-1)d
t(56) is what your looking for so don't worry about the tn.
a is your first term,
a = 15.
n is the position of the term you are looking for, n = 56.
And d is the common difference, you find this by taking t2 and subtracting t1. t2=18 and t1=15.
d = 18 - 15 = 3
Inputting it all into the formula you get,
t(56) = 15 + (56-1)(3)
term 56 = 180.
You use this formula to find any term in a sequence provided you are given enough info. You can also manipulate it if you are asked to find something else like the first term(a), common difference(d) or term position(n). It just depends on what the question is asking and what information you are given. :)
Hope this helps!

7 0

3 years ago

Find the area of each figure

kotegsom [21]

8x10 = 80
4x4 = 16
2x4 divided 2 = 4
80+16+ 4 = 100

5 0

3 years ago

Show 2 different solutions to the task.

laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression $n^2+n$

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then $k^2+k$ is even integer