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Sav [38]
4 years ago
9

G(x) = -2x2 + 3x - 5

Mathematics
1 answer:
vredina [299]4 years ago
3 0
What are you asking about the equation? :3
You might be interested in
Find the product.<br> 5x2.2y2
ArbitrLikvidat [17]

5x2 - 2y2 Answer:

Step-by-step explanation:

3.1      Factoring:  5x2-2y2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  5  is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

8 0
4 years ago
Read 2 more answers
Find the value of the expression 4*2-6+8*3+4
chubhunter [2.5K]

Multiple: 4 * 2 = 8

Subtract: 8 - 6 = 2

Multiple: 8 * 3 = 24

Add: 2 + 24 = 26

Add: 26 + 4 = 30.

4 0
4 years ago
HELP URGENT!! ILL GIVE BRAINLIEST
Luba_88 [7]

Answer:

I think its 21.34 sorry if i am wrong

6 0
3 years ago
Read 2 more answers
In the year 2003, a person bought a new car for $17500. For each consecutive year after that, the value of the car depreciated b
grandymaker [24]

Answer:

$12320

Step-by-step explanation:

Given data

Cost of car= $17500

rate of depreciation= 11%

duration= 2003 - 2006= 3 years

Let us apply the compound interest formula

A= P(1-r)^t

Note the negative sign(this is because of the depreciation)

A=17500(1-0.11)^3

A= 17500(0.89)^3

A=  17500*0.704

A= $12320

Hence the value of the car is $12320

6 0
3 years ago
Recall the equation for a circle with center (h,k) and radius r. At what point in the first quadrant does the line with equation
IgorC [24]

Answer:

At intersection

x=2.68

y=5.34

Step-by-step explanation:

Equation of circle with center (h,k) and radius r is

(x-h)^{2}+(y-k)^{2}=r^2\\\\With\,\, center\,\,(0,4)\,\, and\,\, r=3\\\\(x-0)^{2}+(y-4)^{2}=3^2\\\\x^2+(y-4)^{2}=9---(1)\\\\Equation\,\,of intersecting\,\,line\\y=0.5x+4---(2)

To find point of intersection:

From (2)

x=\frac{y-4}{0.5}=2(y-4)\\\\x^2=4(y-4)^{2}\\\\Put\,\,in\,\,(1)\\\\4(y-4)^{2}+(y-4)^{2}=9\\\\5(y-4)^{2}=9\\\\y-4=\frac{3}{\sqrt{5}}\\\\y=1.34+4\\\\y=5.34\\\\x=2(5.34-4)\\\\x=2(0.34)\\\\x=2.68

At intersection

x=2.68

y=5.34

This point of intersection can be checked in graph attached below

3 0
3 years ago
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