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3 years ago

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PLZ HELP 100 POINTS A triangle has two sides with lengths 7 m and 12 m.Which of the following lengths could represent the length

of the third side? Choose all that apply.4 7 10 17 19

1 answer:

Vinil7 [7]3 years ago

3 0

Answer:

7, 10, 17

Step-by-step explanation:

4m can' t be the third side because the second side, 12m must be less than the sum of the first and third sides and can't be 19m because 19 must be less than the sum of the first and second sides.

As a rule, the measure of a side of a triangle must be less than the sum of the measures of the 2 other sides

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Operations with Radical Expressions

lisov135 [29]

Answer: $30\sqrt{11}$

<u>Step-by-step explanation:</u>

$3\sqrt{50} * \sqrt{22}$

= $3\sqrt{5*5*2} * \sqrt{2*11}$

= $3\sqrt{5*5*2*2*11}$

= $3*5*2\sqrt{11}$

= $30\sqrt{11}$

******************************************

Answer: $6\sqrt{30}$

<u>Step-by-step explanation:</u>

$\sqrt{20} * \sqrt{3} * \sqrt{18}$

= $\sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}$

= $\sqrt{2*2*5*3*3*3*2}$

= $2*3\sqrt{5*3*2}$

= $6\sqrt{30}$

********************************************

Answer: $-\sqrt{5}$

<u>Step-by-step explanation:</u>

$4\sqrt{20} - 3\sqrt{45}$

= $4\sqrt{2*2*5} - 3\sqrt{3*3*5}$

= $4*2\sqrt{5} - 3*3\sqrt{5}$

= $8\sqrt{5} - 9\sqrt{5}$

= $-\sqrt{5}$

********************************************

Answer: $4\sqrt{5}$

<u>Step-by-step explanation:</u>

$2\sqrt{5} + 3\sqrt{5} - \sqrt{5}$

= $(2+3-1)\sqrt{5}$

= $4\sqrt{5}$

********************************************

Answer: $46\sqrt{2}$

<u>Step-by-step explanation:</u>

$4\sqrt{32} + 6\sqrt{50}$

= $4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}$

= $4*2*2\sqrt{2} + 6*5\sqrt{2}$

= $16\sqrt{2} + 30\sqrt{2}$

= $46\sqrt{2}$

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4 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.

$1-0.99^n\geq 0.95\\0.99^n\leq 1-0.95\\0.99^n\leq 0.05\\n\geq 297$

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fgiga [73]

I'd say centimeters, if that's what you're looking for. Maybe 1-2 cm.

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bonufazy [111]

Answer:

30.35

Step-by-step explanation:

Please mark me as brainliest it would mean a lot

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3 years ago

You have 80 pieces of fabric to make a wall hanging. Each piece of fabric is a square with a side length of 5 inches. You use as

tensa zangetsu [6.8K]

Okay. fist off don't think of them as 5 units each, but 1. so if you were to put it on graphing paper and box squares each time. you would be able to get 8 in for both sides to make a square. Area then would be 1600ft squared because 8 ×5 is 40 and 40×40 is 1600. then you calculate how many squares you used. 8×8=64. and 80-64=16 so 16 pieces are left over. then 9×9 (increasing the square) is 81. so 17 pieces to increase it.

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3 years ago

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