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Alex787 [66]
3 years ago
8

PLZ HELP 100 POINTS A triangle has two sides with lengths 7 m and 12 m.Which of the following lengths could represent the length

of the third side? Choose all that apply.4 7 10 17 19
Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

7, 10, 17

Step-by-step explanation:

4m can' t be the third side because the second side, 12m must be less than the sum of the first and third sides and can't be 19m because 19 must be less than the sum of the first and second sides.

As a rule, the measure of a side of a triangle must be less than the sum of the measures of the 2 other sides

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Step-by-step explanation:

Keeping,  one angle FDE, many triangles are possible since length of no segment is fixed and only one angle is fixed.

At many instances, triangle ABC and DEF have same angle measurements. Referring to the image attached here.

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Round each number to the place of the underlined digit 32.65
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3 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
enot [183]

Answer:

P(x < 3) = 25\%

E(x) = 3

Step-by-step explanation:

The given parameters can be represented as:

\begin{array}{ccccccc}x & {5} & {4} & {3} & {2} & {1}& {0} & P(x) & {25\%} & {30\%} & {20\%} & {15\%} & {5\%} & {5\%} \ \end{array}

Solving (a): P(x < 3)

This is calculated as:

P(x < 3) = P(x = 0) + P(x = 1) + P(x =2) ----- i.e. all probabilities less than 3

So, we have:

P(x < 3) = 5\% + 5\% + 15\%

P(x < 3) = 25\%

Solving (b): Expected number of events

This is calculated as:

E(x) = \sum x * P(x)

So, we have:

E(x) = 5 * 25\% + 4 * 30\% + 3 * 20\% + 2 * 15\% + 1 * 5\% + 0 * 5\%

E(x) = 125\% + 120\% + 60\% + 30\% + 5\% + 0\%

E(x) = 340\%

Express as decimal

E(x) = 3.40

Approximate to the nearest integer

E(x) = 3

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What are the answer choices??


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The answer is the first one, impossible. This is because it shows that there are red and black cards, but never mentions that there are blue cards at all. This also means there are no blue cards. How could you get a blue card when there are none? It's impossible. 
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3 years ago
Read 2 more answers
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