By moving point G, how many triangles is it possible to draw, keeping the measure of just one angle constant (in this case, m∠FD
E)? In how many instances are all three angle measures of ∆DEF equal to those of the original triangle, ∆ABC?
1 answer:
Step-by-step explanation:
Keeping, one angle FDE, many triangles are possible since length of no segment is fixed and only one angle is fixed.
At many instances, triangle ABC and DEF have same angle measurements. Referring to the image attached here.
As point G moved on the ray EF, many triangles with same angle measurements as of ABC can be formed.
You might be interested in
Answer:
A: 360
Step-by-step explanation:
Split the trapezoid into 2 shapes
Then find the area of the rectangle on the left:
18 × 15 = 270 square yards
Now for the triangle, first find the base by subtracting the 2 parallel lines:
25 - 15 = 10 yards
0.5(10 × 18) = 90 square yards
Add both areas to find total area:
270 + 90 = 360 square yards
All this can be seen in the figure below:
