Answer:
I wanna say its B. Vera's only
Answer:
(3, 0) and (5, 0)
Step-by-step explanation:
we have

we know that
The x-intercepts are the values of x when the value of y is equal to zero
so
For y=0

The formula to solve a quadratic equation of the form
is equal to

in this problem we have
so

substitute in the formula





so
x=3, x=5
therefore
The x-intercepts are (3,0) and (5,0)
Because

therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k = constant.
Because f(3) = 4, therefore k =4.
The polynomial is
f(x) = 2x³ + 10x² - x - 6x² - 30x + 3 + 4
= 2x³ + 4x² - 31x + 7
Answer: f(x) = 2x³ + 4x² - 31x + 7
assuming 
Then the column values for base five here are
5³ 5²

We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x
→ 19 - 15 = 4
and 4 = 4 × 
Thus
= 
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219