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KatRina [158]
3 years ago
13

In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co

llege, and 30% of the students were in the Education College. To see whether the proportions have changed, a random sample of 300 students from ABC University was selected. Ninety of the sample students are in the Business College, 120 are in the Liberal Arts College, and 90 are in the Education College. Refer to Exhibit 12-4. This problem is an example of a _____. a. multinomial population b. normally distributed variable c. uniformly distributed variable
Mathematics
1 answer:
KIM [24]3 years ago
4 0

Answer:

A. Multinomial population

Explanation:

A multinomial population has categorical data. In other words data in this form has different classes in which data is grouped into. These classes do not overlap and are more than two as opposed to binomial populations that have just two outcome variables or data categories. For example in the above data, we see that data is grouped into three categories:students in business college, students in liberal art college and students in education college

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Leokris [45]
Lamar used 80% of his data, so he used a greater percentage.
5 0
3 years ago
Read 2 more answers
A travel agency has 2,106 people registered for a trip. Each tour bus can seat 54 people.
mariarad [96]

Answer:

39 buses

Step-by-step explanation:

2,106 ÷ 54 = 39

8 0
2 years ago
F(x)=2x+3/4x+5<br>find f(-9)<br>​
mylen [45]

\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

f(x) =  \frac{2x + 3}{4x + 5} \\

For f(-9), put "-9" for every value of "x".

↬f( - 9) =  \frac{2( - 9) + 3}{4( - 9) + 5}\\

↬ f(-9) =  \frac{ - 18 + 3}{ - 36 + 5} \\

↬ f(-9) =  \frac{ - 15}{ - 31}\\

↬ f(-9)=  \frac{15}{31}\\

↬f(-9)=  0.48\\

\bold{ \green{ \star{ \red{Mystique35}}}}⋆

6 0
3 years ago
Read 2 more answers
The patient recovery time from a particular surgical procedure is normally distributed with a mean of 5.3 days and a standard de
inna [77]

Answer:

<em>The probability of spending between 4 and 7 days in recovery</em>

<em>P(4≤x≤7) = 0.5445</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given mean of the Population μ = 5.3 days

Given standard deviation of the population 'σ' = 2 days

Let 'X' be the random variable in normal distribution

Let    x₁ = 4

Z_{1} = \frac{x_{1}-mean }{S.D} = \frac{4-5.3}{2} = -0.65

Let    x₂ = 7

Z_{2} = \frac{x_{2}-mean }{S.D} = \frac{7-5.3}{2} = 0.85

<u><em>Step(ii):-</em></u>

<u><em>The probability of spending between 4 and 7 days in recovery</em></u>

<em>P(4≤x≤7) = P(-0.65≤Z≤0.85)</em>

<em>              =  P(Z≤0.85) - P(Z≤-0.65)</em>

<em>             = 0.5 + A( 0.85) - ( 0.5 - A(-0.65) </em>

<em>             = 0.5 + A( 0.85) -  0.5 +A(0.65)   ( ∵A(-0.65) = A(0.65)</em>

<em>            =   A(0.85) + A(0.65)</em>

<em>           = 0.3023 + 0.2422</em>

<em>          = 0.5445</em>

<u><em>Final answer:</em></u><em>-</em>

<em>The probability of spending between 4 and 7 days in recovery</em>

<em>P(4≤x≤7) = 0.5445</em>

<em>            </em>

6 0
3 years ago
Part A From the choices provided, select all the questions that represent statistical questions. What was the temperature at 5:0
Tju [1.3M]
I would answer but I’m in 6th grade and I don’t know how to
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2 years ago
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