Answer:
These lines are perpendicular.
Step-by-step explanation:
Put both equations in the slope intercept form of a line.
y = -6x - 8 This is already in the slope intercept form for a line
-x + 6y = 12 Add x to both sides of the equation
6y = x + 12 Divide through the whole equation by 6
y = 1/6x +2
Now we compare the two slopes of -6 and 1/6. They are negative reciprocals of each other. That means that the line are perpendicular.
There are 3600 seconds in 1 hour.
Multiply feet per second by 3600 to get feet in 1 hour:
150 x 3600 = 540,000 feet in 1 hour.
1 mile = 5280 feet.
Divide feet per hour by 5280 to get miles per hour:
540,000 / 5280 = 102.27 miles per hour.
Answer:
x=2
Step-by-step explanation:
y=-3 is a horizontal line so the one that is perpendicular to it is supposed to be vertical
Answer:
r=63
Step-by-step explanation:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
r/3-(21)=0 r
Simplify —
3
r
— - 21 = 0
3 2.1 Subtracting a whole from a fraction
Rewrite the whole as a fraction using 3 as the denominator :
21 21 • 3
21 = —— = ——————
1 3
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
ANSWER: 32 five-dollar bills
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EXPLANATION:
Let x be number of $5 bills
Let y be number of $10 bills
Since we have total of 38 bills, we must have the sum of x and y be 38
x + y = 38 (I)
Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):
5x + 10y = 220 (II)
System of equations:
![\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.](https://tex.z-dn.net/?f=%20%5Cleft%5C%7B%20%5Cbegin%7Baligned%7D%20x%20%2B%20y%20%26%3D%2038%20%26%26%20%5Ctext%7B%28I%29%7D%20%5C%5C%205x%20%2B%2010y%20%26%3D%20220%20%26%26%20%5Ctext%7B%28II%29%7D%20%5Cend%7Baligned%7D%20%5Cright.%20)
Divide both sides of equation (II) by 5 so our numbers become smaller
![\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.](https://tex.z-dn.net/?f=%20%5Cleft%5C%7B%20%5Cbegin%7Baligned%7D%20x%20%2B%20y%20%26%3D%2038%20%26%26%20%5Ctext%7B%28I%29%7D%20%5C%5C%20x%20%2B%202y%20%26%3D%2044%20%26%26%20%5Ctext%7B%28II%29%7D%20%5Cend%7Baligned%7D%20%5Cright.%20)
Rearrange (I) to solve for y so that we can substitute into (II)
![\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}](https://tex.z-dn.net/?f=%20%5Cbegin%7Baligned%7D%20x%20%2B%20y%20%26%3D%2038%20%26%26%20%5Ctext%7B%28I%29%7D%20%5C%5C%20y%20%26%3D%2038%20-%20x%20%5Cend%7Baligned%7D%20)
Substituting this into equation (II) for the y:
![\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}](https://tex.z-dn.net/?f=%20%5Cbegin%7Baligned%7D%20x%20%2B%202y%20%26%3D%2044%20%26%26%20%5Ctext%7B%28II%29%7D%20%5C%5C%20x%20%2B%202%2838%20-%20x%29%20%26%3D%2044%5C%5C%20x%20%2B%2076%20-%202x%20%26%3D%2044%20%5C%5C%20-x%20%26%3D%20-32%20%5C%5C%20x%20%26%3D%2032%20%5Cend%7Baligned%7D%20)
We have 32 five-dollar bills
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If we want to finish off the question, use y = 38 - x to figure out number of $10 bills
![y = 38 - 32 = 6](https://tex.z-dn.net/?f=y%20%3D%2038%20-%2032%20%3D%206)
32 five-dollar bills and 6 ten-dollar bills