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blsea [12.9K]
4 years ago
10

Simplify C^5 x c Plz can someone figure it out cuz I don’t get it

Mathematics
2 answers:
Fofino [41]4 years ago
5 0

Answer:

c^6

Step-by-step explanation:

So, c is the same as c^ 1 ... therefore

c^5 x c

= c^5 x c^1

When we multiply two numbers with same base and different exponent, we add the exponents which in this case as 5 and 1

So c^5 x c^1

= c^(5+1)

= c^6

This is the simplest form

spin [16.1K]4 years ago
4 0

Answer: c⁶

<u>Step-by-step explanation:</u>

Notes: A variable without a given exponent has an "invisible" exponent of 1.

When multiplying two values with the same base, add the exponents.

\bold{c^5 \times c\qquad \rightarrow \quad c^5 \times c^1\quad =\quad c^{5+1}\quad = \large\boxed{c^6}}

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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
What is 34% of 60000000
Ainat [17]

(Lets hope i'm right :p)


The first thing you do is make "34%" into a fraction. That would be 1/34.

After, you would multiply.


1/4 x 60000000/1 = ?

(Use cross multiply if you know)

60000000 divided by 4 = 15000000

1/1 x 15000000/1 = 15000000/1 OR 15000000


Answer: 15000000/1 or 15000000

<em>Tell me if i'm wrong so I can prevent this in the future! Have a lovely day!</em>

                                                                                                     ~Pooch ♥


7 0
4 years ago
Read 2 more answers
Identify a pair of similar triangles How can you tell the difference between Side-Side-Side, Side-Angle-Side, Angle-Side-Angle,
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Step-by-step explanation:

SSS

SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. For example: is congruent to: (See Solving SSS Triangles to find out more) If three sides of one triangle are equal to three sides of another triangle, the triangles are congruent

SAS

The Side Angle Side postulate (often abbreviated as SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

ASA

ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal. For example: is congruent to: (See Solving ASA Triangles to find out more)

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The Angle Angle Side postulate (often abbreviated as AAS) states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent.

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The midpoint of is
Degger [83]

Answer:

The answer is 0/2

Step-by-step explanation:

The second y - the first y / the second x - the first x.

Step 1: 1 - 1 / 5 - 3

Step 2: 0 / 5 - 3

Step 3: 0 / 2

8 0
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HELP PLEASE I DON'T UNDERSTAND
liraira [26]
If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
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3 years ago
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