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Umnica [9.8K]
3 years ago
5

A chemist has 30% and 40% solutions of acid available. How many liters of each solution should be mixed to obtain 65 liters of 3

2% acid solution?
liters of 30% acid
liters of 40% acid
Mathematics
1 answer:
mars1129 [50]3 years ago
5 0

Answer:

30 = 80 %

40= 20 %

Step-by-step explanation

I'm sorry for not writing how to do it but it's something like if 30 = 100 then if we had 40 occupying 20 percent of that acid then we will get 32 percent

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Considere os logaritmos log3=0,477 , log4=0,602 e / log5=0.699 logaritmos determine o valor de log5 12.
anygoal [31]

Given that :

log3=0.477 , log4=0.602  and log5=0.699

Now , as you know that

\log\text{MN}=\log M +\log N

We have to find the value of

\log_{5}12

So,\log_{5}12=\frac{\log12}{ \log5}             

                         = \frac{\log 4+\log 3}{\log 5}\\

Now Putting the values of log3, log4 and log5 in the above expression

\log_{5}12=\frac{0.477 +0.602}{0.699}

                    =1.0079/0.699

                     =1.5436..

                     =1.544 (approx)

So, the value of \log_{5}12 is 1.544(approx).



5 0
3 years ago
Help me ASAP PLEASE lateral surface area of the triangular prism :)
Lerok [7]

Answer:

15+15+40+40+40= 150

Step-by-step explanation:

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15

Rectangle x3]

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Your answer is <u>150cm square.</u>

<u>But you do not have that option so I would pick the closes one if I were you. Have a good day.</u>

4 0
3 years ago
What is social stratification?
MrRissso [65]

Answer:

The answer is B

Step-by-step explanation

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3 0
2 years ago
Which equation can be used to represent "six added to twice the sum of a number and four is equal to one-half of the difference
UkoKoshka [18]

Answer:

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6 0
3 years ago
the area of a square whose sides have length x cm is increasing at the rate of 12cm²/s. how fast is the length of a side increas
katovenus [111]

Answer:

0.67 cm/s

Step-by-step explanation:

The area of a square is given by :

A=x^2 ....(1)

Where

x is the side of a square

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Differentiating equation (1) wrt t.

\dfrac{dA}{dt}=2x\times \dfrac{dx}{dt}

When A = 81cm²​, the side of the square, x = 9 cm

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So, the length of the side of a square is changing at the rate of 0.67 cm/s.

4 0
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