Answer:
49646
Step-by-step explanation:
Answer:
Square.
Step-by-step explanation:
given J(-4,2) || K(0,3) || L(1,-1) || M(-3,-2)
given below the visual answer.
OR
you can find the distance of coordinate to coordinate:
Distance of JK
√(-4-0)² + (2-3)²
√17
Distance of KL
√(0-1)²+(3--1)²
√17
Distance of LM
√(1--3)²+(-1--2)²
√17
Distance of MJ
√(-3--4)²+(-2-2)²
√17
All sides are similar of √17 , so its a square.
1.-28×-28×-28+13×13×13+16×16×16
=21,952+2,197+4,096
=28,245.
2.12×12×12+-7×-7×-7+-5×-5×-5
=1,728+-343+-125
=1,260
A = -2
b = 4
c = -3
They are the coefficients to the terms in the equation<span />
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L