You know that you need two already to make one hexagon. So, if you multiply, or add two four times, 2+2+2+2, you would get eight.
Answer:
C) S = {F, PF, PPF, PPP}
Step-by-step explanation:
For this case, we know that a person is trying to gain access to a bank vault and needs to go through 3 security doors, and we know that if the person does not pass a door, then he/she has no other attempts. We denote P= Successful pass , F= Failed pass
And we are interested on the sample space, we need to remember that the sample is the set with all the possible values for an experiment.
For this case the person can fail at the 1,2 or 3 try
For the case that fails at the 1 try we have F
For the case that fails at the 2 try we have PF
For the case that fails at the 3 try we have PPF
And the last option is that the person not fails at any try and we have PPP
So then the sample space would be given by:
C) S = {F, PF, PPF, PPP}
-x² - x + 6
First thing I would do is distribute out that negative. Your new problem is:
- (x² + x - 6)
Now, factor the inside. We need to find products of - 6 that when added together have a sum of positive 1. They are 3 and - 2.
- (x² + 3x - 2x - 6)
Group together and find your factors. I'm going to short cut and go right to them for the sake of space and time.
- (x + 3)(x - 2)
Your answer is Option B
I think its 91.
NOT Guaranteed this is the Answer. Best of luck to you.
