Answer:
61 + 4x = y
Step-by-step explanation:
61 : starting tree height
4x : 4 times however many months pass
y : total height after x months.
Answer:
4....
Step-by-step explanation:
Okay! Free points, uh... 2... and 2... put together... is... four...
Answer:
18.95%
Step-by-step explanation:
In this case what we must do is calculate the probability of eating a jelly treats first and then another jelly treats, being the final probability the multiplication of these events.
We know that there are 20 in total and that initially there are 9 jelly treats, so the first event is the probability:
9/20
And the second event, with one less in each, would be:
8/19
The final probability then:
9/20 * 8/19 = 0.1895
So the probability of this happening is 18.95%
This is an exponential equation that can be represented by the following:
f(x) = a(b)^x
In this case...
25143 = a(0.66)^3
25143 is the population after 3 hours.
3 is the amount of time in hours.
0.66 represents the percent of the population remaining after each hour (66% as there is a 34% decline each hour).
We must solve for a, which is the initial population.
First, simplify (0.66)^3 to 0.2874.
25143 = 0.2874a
Now divide both sides by 0.2874 to isolate a.
a = 87455
There were initially 87,455 people within the city. I wouldn't want to be in that place!
If the given differential equation is
then multiply both sides by 
:
The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to 
, recalling that 
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)
Solve for 
:
![\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csec%28x%29%20%2B%20C%20%5Ccsc%28x%29%7D%3C%2Fp%3E%3Cp%3Ewhich%20follows%20from%20%5Btex%5D%5Ctan%28x%29%3D%5Cfrac%7B%5Csin%28x%29%7D%7B%5Ccos%28x%29%7D)
.
