Help me answer these math problems. They are due by 10:00 PM Tonight. Please answer them carefully.

Mathematics

1 answer:

Romashka [77]2 years ago

5 0

Answer:

. Kelsey takes out a loan for $6000 to start a business after high school. The bank charges her 8% simple interest for the loan. Term is five years. After 5 years , what will the balance be for the repayment of this loan? (round to nearest cent)

Step-by-step explanation:

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Find the product of a) 1/10×5/6

kodGreya [7K]

Answer:

1/12

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4 0

3 years ago

Please help me with these questions

Mars2501 [29]

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

$\spadesuit\; Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}$

Given Points are (8 , 30) and (18 , 60)

here x₁ = 8 and x₂ = 18 and y₁ = 30 and y₂ = 60

$\spadesuit\; Slope(m) = \frac{30 - 60}{8 - 18} = \frac{-30}{-10} = 3$

We know that the form of line passing through point (x₀ , y₀) and having slope m is : y - y₀ = m(x - x₀)

Here the line passes through the point (8 , 30)

⇒ x₀ = 8 and y₀ = 30

We found Slope(m) = 3

Substituting all the values in the standard form, We get :

Equation of the line : y - 30 = 3(x - 8)

Let d be the x-intercept of this line

⇒ The line passes through the point (d , 0) as at x-intercept, y-coordinate is zero.

⇒ 0 - 30 = 3(d - 8)

⇒ 3d - 24 = -30

⇒ 3d = -30 + 24

⇒ 3d = -6

⇒ d = -2

⇒ The x - coordinate of the x-intercept of the line is -2

6 0

3 years ago

9. A ladder of length 23 feet leans against the side of a building. The angle of elevation of the ladder is 76. Find the distanc

irakobra [83]

<h3>Answer:</h3>

B) 22.32 feet

$\quad\rule{300pt}{1pt}$

<h3>Solution:</h3>

we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

$\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull$