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ryzh [129]
3 years ago
13

How do you factor out the coefficient of the variable

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0
Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.
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The perimeter of a rectangle is 52. The length is 2 more than 2 times the width. Find the width and length.
Arlecino [84]
Formula for the perimeter of a rectangle = 2(L + W).
let the width be x
length = 2 + 2x
substitute respectively
52 = 2(2 + 2x + x)
52 = 2 (2 + 3x)
52 = 4 + 6x
52 - 4 = 6x
48 = 6x
divide both sides by 6
48/6 = 6x/6
8 = x
width = 8
length = 2 + 2x = 2 + 2(8) = 2 + 16 = 18
4 0
4 years ago
What is the value of X?<br> A 57 B 48 C 38 D 28
olga_2 [115]

Answer: D. 28

Step-by-step explanation:

The 3 interior angles of a triangle always add up to 180

Soooo:

95 + 57 = 152

180 - 152 = 28

5 0
4 years ago
Please help with this
Elena L [17]

Here

radius( r) =12/2=6 in.

height(h)=13 in.

now,

volume of hemisphere(V1)=

\frac{2}{3} \pi \:  {r}^{3}  =  \frac{2}{3}\pi  {6}^{3}  = 144\pi \: cu. \: in.

volume of cylinder(V2)=

\pi {r}^{2} h = \pi \times  {6}^{2}  \times 13 = 468\pi \\

now total volume=V1+V2

=144Pi +468pi

=212pi

8 0
4 years ago
I need help it’s for a very hard test
Mumz [18]

Answer:

C

Step-by-step explanation

This has a factor of 6% or 0.06. But, you are adding and not subtracting so it is 1.06. ( If you multiply by a number less than 1 then it is actually dividing) So C is the only on that is correct.

6 0
3 years ago
Can someone please help and explain its due in a littleee
jek_recluse [69]

f(x) =  {x}^{2}  - 3x + 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (-1)

f( - 1) =  {( - 1)}^{2}  - 3 \times ( - 1) + 2  \\  \\   1  + 3 + 2  \\  \\   6.

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (z)

f(z) =  {z}^{2}  - 3 \times z + 2  \\  \\  {z}^{2}  - 3z + 2  \\  \\  {z}^{2} - 2z - z + 2 \\  \\ z(z - 2) - 1(z - 2) \\  \\ (z - 1)( z -2 ) \\  \\ (z - 1) = 0  \:  \: , \:  \: (z - 2) = 0\\  \\ z =  1 \:,  \: 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (x+1)

f(x + 1)  = {x}^{2}  -  3x + 2 \\  \\  {(x + 1)}^{2}  - 3 (x + 1) + 2 \\  \\  {x}^{2}  + 1 + 2x - 3x - 3 + 2 \\  \\  {x}^{2}  - x \\  \\ x(x - 1) \\  \\ x(x - 1) = 0   \\  \\  x - 1 =  \frac{0}{x}  \\  \\ x - 1 = 0 \\  \\ x = 1.

<h2>•••••••••••••••••••••••••••••••••</h2>

put x = (√2 + 1 )

f( \sqrt{2}  + 1) =  {x}^{2}  - 3x + 2 \\  \\  {( \sqrt{2} + 1) }^{2}  - 3( \sqrt{2}  + 1) + 2 \\  \\ 2 + 1 +  2\sqrt{2}  - 3 \sqrt{2}  - 3 + 2 \\  \\ 3 - 1 \sqrt{2}  - 1 \\  \\ 2 -  \sqrt{2}  \\   \\  2 - 1.4 (optional \:  \:  \: steps)\\  \\ 0.6 \:  \:

4 0
2 years ago
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