Answer:
Step-by-step explanations:
10x - 2x
8x
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
First you make the mixed numbers/fractions into improper fractions. After that, you must find the common denominator, the LCM of 9 and 6 (for the 2nd problem). After that, if you can, simplify the fraction to lowest terms, which also includes making it a mixed number/fraction.
I hope this helps! :)
Yes you are correct!
you first have to get rid of the number next to the variable m. so you have to subtract 9 to get rid of the variable. then you subtract 9 from both sides and get that answer.
