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Alchen [17]
3 years ago
8

Suppose compact fluorescent light bulbs last, on average, 11,500 hours. The distribution is normal and the standard deviation is

400 hours. What percent of light bulbs burn out within 12,300 hours?
Mathematics
1 answer:
juin [17]3 years ago
6 0

Answer:

2.275%

Step-by-step explanation:

The first thing to do here is to calculate the z-score

Mathematically;

z-score = (x-mean)/SD

from the question, x = 12,300 hours , mean = 11,500 hours while Standard deviation(SD) = 400 hours

Plugging the values we have;

z-score = (12,300-11,500)/400 = 800/400 = 2

Now, we want to calculate P(z ≤ 2)

This is so because we are calculating within a particular value

To calculate this, we use the z-score table.

Mathematically;

P(z ≤ 2) = 1 - P(z > 2) = 1 - 0.97725 = 0.02275

To percentage = 2.275%

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A number of robbers were discussing how best to share some stolen rolls of
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Answer:

83

Step-by-step explanation:

Let the number of robbers be x

If they share 6 rolls each, the tota rolls will be 6x and since they have five remainder, the overall total is then 6x+5

In case they share 7 rolls each, it means they have 7x rolls but here they will be less 8 rolls hence 7x-8 is the overall total.

Equating these two

7x-8=6x+5

Arranging similar terms

7x-6x=8+5

x=13

Therefore, the robbers are 13

The rolla they have will be

6(13)+5=83

Or

7(13)-8=83

6 0
3 years ago
A circle has an area of 50 square meters what is the diameter
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Misha Larkins [42]

Answer:

x > -1

Step-by-step explanation:

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It is estimated that 89% of senior citizens suffer from sleep disorders and 9% suffer from anxiety. Moreover, 5% of senior citiz
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If my calculations are incorrect, then sorry ;/

- <u><em>❤ 7272033Alt ❤</em></u>

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