3 years ago

A triangle with side lengths 33 feet, 56 feet and 65 feet is a right triangle.

Mathematics

2 answers:

oee [108]3 years ago

7 0

Its true because : 33^2 + 56^2 = 65 ^2

kogti [31]3 years ago

6 0

Your answer would be true

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notsponge [240]

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Step-by-step explanation:

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3 years ago

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fenix001 [56]

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3 years ago

a pet store buys bags of dog food for 30.00 dollars per bag and sells them for 54.00 dollars per bag. What is the percent markup

Alenkinab [10]

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3 years ago

Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.

Mandarinka [93]

k, n - integers

2k+1 - an odd integer

2n+1 - another odd integer

The product of them:

(2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

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The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

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4 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago