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3 years ago

What is the next step in constructing an angle (MNO ) congruent to the given angle (ABC ) with a straightedge and a compass?

Mathematics

1 answer:

nata0808 [166]3 years ago

5 0

The next step in constructing an angle (MNO ) congruent to the given angle (ABC ) is, using N as the center and the same radius as before, draw an arc that intersects |NO|. label the arc PQ where Q intersects |NO|.

To construct angle MNO congruent to the given angle ABC, the following conditions must be satisfied:

The two angles must be equal (∠ABC = ∠MNO).
The radius of the two triangles must be equal.
The radius from center N must be equal to radius BA and BC.
The radius of angle MNO is NO and it must equal BA and BC

Thus, we can conclude that, the next step in constructing an angle (MNO ) congruent to the given angle (ABC ) is, using N as the center and the same radius as before, draw an arc that intersects |NO|. label the arc PQ where Q intersects |NO|.

Learn more about construction of congruent angles here: brainly.com/question/20097419

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3 years ago

A parallelogram has vertices E(1, 4), F(5, 3), G(−3, 1), and H(1, 0). What are the coordinates of the midpoint of each diagonal?

kozerog [31]

Check the picture below.

now, the diagonals cut each other in two equal halves, thus, the midpoint of GF is the same coordinates as the midpoint for EH, so let's check what the midpoint for GF is then

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
G&({{ -3}}\quad ,&{{ 1}})\quad 
% (c,d)
F&({{ 5}}\quad ,&{{ 3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
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3 years ago

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iren [92.7K]

Answer:

None of the given option corresponds to the answer.

Step-by-step explanation:

The parabola has its axis of symmetry parallel to the x-axis and is represented by the following expression:

$x - h = 4\cdot p \cdot (y-k)^{2}$

Where:

$h$ , $k$ - Components of the vertex location, dimensionless.

$p$ - Absolute distance of focus with respect to vertex, dimensionless.

The absolute distance is determined by following formula:

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Where $x_{F}$ is the horizontal component of focus with respect to origin.

If $h = -2$ , $k = -4$ and $x_{F} = -4$ , the absolute distance and the equation that represents the parabola is:

$p = -4+2$

$p = -2$

$x +2 = -8\cdot (y+4)^{2}$

None of the given option corresponds to the answer.

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4 years ago

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Step-by-step explanation:

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