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babymother [125]
2 years ago
13

What is the next step in constructing an angle (MNO ) congruent to the given angle (ABC ) with a straightedge and a compass?

Mathematics
1 answer:
nata0808 [166]2 years ago
5 0

The next step in constructing an angle (MNO ) congruent to the given angle (ABC ) is, using N as the center and the same radius as before, draw an arc that intersects |NO|. label the arc PQ where Q intersects |NO|.

To construct angle MNO congruent to the given angle ABC, the following conditions must be satisfied:

  • The two angles must be equal (∠ABC = ∠MNO).
  • The radius of the two triangles must be equal.
  • The radius from center N must be equal to radius BA and BC.
  • The radius of angle MNO is NO and it must equal BA and BC

Thus, we can conclude that, the next step in constructing an angle (MNO ) congruent to the given angle (ABC ) is, using N as the center and the same radius as before, draw an arc that intersects |NO|. label the arc PQ where Q intersects |NO|.

Learn more about construction of congruent angles here: brainly.com/question/20097419

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What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
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Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


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2 years ago
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atroni [7]

By applying the equation of dilation, the coordinates of the vertices of the triangle ABC are A'(x, y) = (-12, 0), B'(x, y) = (0, -9) and C'(x, y) = (-12, -9).

<h3>How to find the image of a triangle</h3>

A dilation is a type of <em>rigid</em> transformation. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distances are conserved.

There is a triangle and its image must be a triangle, the <em>new</em> triangle is found by transforming the three vertices of the prior one following this formula:

A'(x, y) = P(x, y) + k · [A(x, y) - P(x, y)]     (1)

Where:

  • P(x, y) - Center of reflection.
  • A(x, y) - Original vertex
  • A'(x, y) - New vertex
  • k - Dilation factor

If we know that P(x, y) = (0, 0), A(x, y) = (-4, 0), B(x, y) = (0, -3) and C(x, y) = (-4, -3), then the new vertices of the triangle are, respectively:

Point A

A'(x, y) = (0, 0) + 3 · [(-4, 0) - (0, 0)]

A'(x, y) = (-12, 0)

Point B

B'(x, y) = (0, 0) + 3 · [(0, -3) - (0, 0)]

B'(x, y) = (0, -9)

Point C

C'(x, y) = (0, 0) + 3 · [(-4, -3) - (0, 0)]

C'(x, y) = (-12, -9)

Lastly, we draw the two triangles, which are presented in the image attached below.

To learn more on dilations: brainly.com/question/13176891

#SPJ1

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Answer:

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