All categories

2 years ago

Layla has 3/4 of a can of paint. She uses 2/3 of that plant. What fraction of the can did she use?

Mathematics

1 answer:

galben [10]2 years ago

8 0

Answer:

its cuz ur computer is upside down

Step-by-step explanation:

add it all up

You might be interested in

Need help ASAP!!! Pleasee

stira [4]

f ( - 1 ) = - 8 [ approximately ]

f ( 1 ) = - 12 [ approximately ]

4 0

2 years ago

30w^3 -6w --------------- 6w

7nadin3 [17]

$\frac{30w^3-6w}{6w} = \frac{6w(5w^2-1)}{6w} =5w^2-1$

7 0

3 years ago

Read 2 more answers

Angle 3 is a supplement of angle 4. If the m of angle 3 is 100 degrees, what is the m of angle 4?

Triss [41]

Answer: 80

Step-by-step explanation: Supplements mean they add up to 180. is m of 3 is 100, then m of 4 must be 80 to add up to 180. Hope this helps!

7 0

2 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately 923.558 m²

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ 923.558 m²

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

2 years ago

What is the value of x to the nearest tenth?

baherus [9]

Answer:
x
≈
16

Explanation:
Remember Sine of an angle is
opposite side
hypotenuse

So let the hypotenuse be
x
:
sin
(
47
°
)
=
opposite side
x

sin
(
47
°
)
=
12
x

To solve for
x
, divide
sin
(
47
°
)
by
12
:
x
=
12
sin
(
47
°
)

x
≈
16

3 0

2 years ago