There are 4 possible letters to start with.
The pass word is 3 letters long.
The first letter can be A, B, C, D = 4 different letters.
The 2nd letter can be 4 - 1 = 3 letters ( Can't have repeats)
The 3rd letter can be 3-1 = 2 letters ( no repeats)
Number of possible passwords = 4 x 3 x 2 = 24
1. 4 times 6
2. 8 divided by 2
3. 4 squared 2
The answer is 1.
2×3=6
6÷6=1
Answer:
-24.1t^2+3
Step-by-step explanation:
Answer:
Step-by-step explanation:Herely/3fcEdSx's li
nk to the answer:
bit.