Answer:
5ax + 5ay = 5a(x+y)
Step-by-step explanation:
Answer:
a = 9.849
b = 20.25
c = 491.03
Step-by-step explanation:
By using Pythagoras theorem in the right triangle BDC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
BC² = BD² + DC²
a² = 9² + 4²
a = 
a = 
a = 9.8489
a ≈ 9.849 units
By mean proportional theorem,
AD × DC = BD²
b × 4 = 9²
b = 
b = 20.25 units
BY Pythagoras theorem in ΔADB,
AB² = AD² + BD²
c² = b² + 9²
c² = (20.25)² + 9²
c² = 410.0625 + 81
c = 491.0625
c = 491. 063 units
- 16t^2 +144 you can rewriting in this form 144 -16t^2 = (12 -4t)(12+4t)
12-4t=0
12 =4t divide both sides by 4
t=3
hope helped
Answer: original angle = 75°
Its supplement 105°
Its complement = 15°
Step-by-step explanation:
We know that,
- Sum of supplementary angles is 180 degrees.
- Sum of complementary angles is 90 degrees.
Let x be the original angle , then its supplement = 180° - x
its complement = 90° - x
As per given,
180° - x = 7(90° - x)
⇒ 180° - x = 630° - 7x
⇒ 7x- x = 630° -180°
⇒ 6 x = 450°
⇒ x = 75° [divide both sides by 6]
So, original angle = 75°
Its supplement = 180° - 75° = 105°
Its complement = 90° -75° = 15°
Hence, original angle = 75°
Its supplement 105°
Its complement = 15°
<span>First we have to determine the slope of each lines by transforming to the slope-intercept form:
y=(3x-7/)4; m2= ¾y=(12x+6)/5, m3 = 12/5
The formula to be used in the proceeding steps is a=tan^-1(m1-m2)/1+m1m2=tan^-1(m1-m2)/1+m1m2
substituting, a=tan^-1(m1-3/4)/1+3m1/4=tan^-1(m1-12/5)1+12m1/5) =>(4m1-3)/(4+3m1)=(5m1-12)/(5+12m1)m1 = -1applying this slope
y -y1 = m(x-x1)
when y1 = 5 and x1 = 4 then,
y - 5 = -1(x-4)
y = -x +4+ 5 ; y = -x +9</span>
