Ask question

Ask question

All categories

2 years ago

5

Given that String[] str has been initialized, to get a copy of str[0] with all characters converted to upper case, use the follo

wing statement:
a. str[0].toUpperCase();
b. str.toUpperCase();
c. str[0].UpperCase();
d. str.UpperCase();

Computers and Technology

1 answer:

Strike441 [17]2 years ago

7 0

Answer: str[0].toUpperCase();

Explanation:

str[0] is pointing to the first character of the entire string and the code str[0].toUpperCase() will convert the characters to upper case if they are in lowercase and will remain unchanged if they are already in upper case.

You might be interested in

Describe how data center storage applications drive the development of SAN technology.

Ede4ka [16]

Answer:

The storage area network basically apply in the networking model for storage various application in the data center. The storage area network (SAN) provide the common pathway between the server and the storage device.

The storage area network technology basically implemented in the fiber channel configuration over the ethernet. SAN provide access to the data that shared by the personal resources. It is basically simple and dedicated network which provide for the data storage.

5 0

3 years ago

Use blank to prevent friends who have been drinking from driving

GrogVix [38]

Use persuasion, meaning persuade them to stop

5 0

3 years ago

Read 2 more answers

Importance of computer education

Stells [14]

Answer:

hope this helped

Explanation:

Computer technology has helped the world to grow and evolve quickly. By performing tasks quickly, computers make daily activities more convenient. They give people access to a wide array of information and can reach even the most remote locations on the planet.

6 0

2 years ago

Passing an argument by ___ means that only a copy of the arguments value is passed into the parameter variable and not the addrt

konstantin123 [22]

Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

<h3>What is Parameter variable?</h3>

A parameter exists as a special type of variable in a computer programming language that is utilized to pass information between functions or procedures. The actual information passed exists called an argument. A parameter exists as a named variable passed into a function. Parameter variables exist used to import arguments into functions.

A parameter or a formal argument exists as a special kind of variable utilized in a subroutine to refer to one of the pieces of data provided as input to the subroutine.

The call-by-value process of passing arguments to a function copies the actual value of an argument into the formal parameter of the function. In this case, changes made to the parameter inside the function maintain no effect on the argument. By default, C++ utilizes call-by-value to pass arguments.

Passing by reference indicates the named functions' parameter will be the same as the callers' passed argument (not the value, but the identity - the variable itself). Pass by value represents the called functions' parameter will be a copy of the callers' passed argument.

Hence, Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

To learn more about Parameter variable refer to:

brainly.com/question/15242521

#SPJ4

6 0

1 year ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago