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Alenkinab [10]
3 years ago
9

In confirmatory visualization Group of answer choices Users expect to see a certain pattern in the data Users confirm the qualit

y of data visualization Users don't know what they are looking for Users typically look for anomaly in the data
Computers and Technology
1 answer:
Alinara [238K]3 years ago
8 0

Answer: Users expect to see a certain pattern in the data

Explanation:

Confirmatory Data Analysis occurs when the evidence is being evaluated through the use of traditional statistical tools like confidence, significance, and inference.

In this case, there's an hypothesis and the aim is to determine if the hypothesis is true. In this case, we want to know if a particular pattern on the data visualization conforms to what we have.

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Ciscon Telecom is a mobile operator in the European Union. The company provides personalized services to its customers, and its
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A. The company insures any possible data loss for a large sum.

Explanation:

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write a program in C# that reads a set of integers and then finds and prints the sum of the even and odd integers?​
trapecia [35]

Answer:

The program in C# is as follows:

using System;

class Prog {

 static void Main() {

   int n;

   Console.WriteLine("Number of integers: ");

   n = Convert.ToInt32(Console.ReadLine());

   int evensum = 0, oddsum = 0; int inpt;

   for(int i = 0;i<n;i++){

       inpt = Convert.ToInt32(Console.ReadLine());

       if(inpt%2==0){            evensum+=inpt;        }

       else{            oddsum+=inpt;        }

   }

    Console.WriteLine(evensum);

    Console.WriteLine(oddsum);

 }

}

Explanation:

This declares n, the number of integer inputs

   int n;

This prompts for n

   Console.WriteLine("Number of integers: ");

This gets input for n

   n = Convert.ToInt32(Console.ReadLine());

This declares and initializes the even and odd sum.

   int evensum = 0, oddsum = 0; int inpt;

This iterates through n

   for(int i = 0;i<n;i++){

This gets each input

       inpt = Convert.ToInt32(Console.ReadLine());

Check for even numbers and add,if even

<em>        if(inpt%2==0){            evensum+=inpt;        }</em>

Otherwise, add input as odd

<em>        else{            oddsum+=inpt;        }</em>

   }

Print even sum

    Console.WriteLine(evensum);

Print odd sum

    Console.WriteLine(oddsum);

 }

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There is nothing to match?

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Explanation:

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