Dunnow what the formula is for
combinations vs permutations
combos, the order does matter and you can repeat
permutations, the order doesn't matter and once you use something, you can't repeate it
what you do is
(number of choices)^(number of slots y ou have to fill)
in this case
number of choices is 3 (3 fllavors)
number of slots=2 since 2 toppings
3^2=9
9 choices
chocolate-carmael
chocolate-strawberry
chocolate-chocolate
strawberry-carmael
strawberry-chocolate
strawberry-strawberry
carmael-chocolate
carmael-strawberry
carmael-carmael
9 choices
Answer:
Step-by-step explanation:
Step 1: Add -Hy to both sides.
Step 2: Divide both sides by A.
Answer:
140
Step-by-step explanation:
The arithmetic series is 5, 7, 9, 11, ........., 23.
First u have to determine the no. of terms that can be done by using
Tₙ = [a + (n - 1)d]
Tₙ-------nth term
a---------first term
n---------no.of terms in the series
d---------common difference
here a = 5,d = 2.
let it contain n terms Tₙ= [a + (n-1)d]
Substitute Tₙ, a, and d in the equation
23 = 5 + (n - 1)2
Subtract 5 from each side.
18 = (n-1)2
Divide each side by 2
(n - 1) = 9
Add 1 to each side
n = 9 + 1 = 10
The sum of the arithmetic sequence formula: Sₙ= (n/2)[2a+(n-1)d]
Substitute Sₙ, a, n and d in the equation
Sₙ= (10/2)[2(5) + (10-1)2]
Sₙ= (5)[10 + (9)2]
Sₙ= 5[10 + 18]
Sₙ= 5[28] = 140
Therefore the sum of the arithmetic sequence is 140.
Step 1: 0.116 = 116⁄1000
Step 2: Simplify 116⁄1000 = 29⁄250
It is itself a ordered pair