If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the y-axis, it has an equation of (x - h)^2<span> = 4p(y - k)</span><span>, where the </span>focus<span> is (h, k+p) and the </span>directrix<span> is y = k - p. So, we need to determine the values from the equation.
</span><span>y=1/28(x-4)^2-5
</span>(x-4)^2 = 28(y+5)<span>
(h,k) = (4, -5)
p = 7
focus= </span>(h, k+p) = 4,2
directrix = y = k - p = -12
Hope this answers the question.
Binomial? I'm not sure what the options are but this is a binomial.
Neighborhood A :
first, put the numbers in order...
2,[2,2],4,(4),5,[5,5],5
5 number summary :
minimum = 2
Q1 = 2
Q2 (median) = 4
Q3 = 5
maximum = 5
IQR = Q3 - Q1......5 - 2 = 3...so the IQR = 3
Neighborhood B :
1,[1,2],2,(3),4,[5,5],12
5 number summary :
minimum = 1
Q1 = (1 + 2) / 2 = 3/2 or 1.5
Q2 (median) = 3
Q3 = 5
maximum = 12
IQR = Q3 - Q1....5 - 1.5 = 3.5
are the box plots symmetrical ?
Neighborhood A : the median is 4.....the minimum is 2....so thats 2 spaces from the median...the maximum is 5....so thats 1 space from the median...and being that they are not the same distance from the median, ur box plot is skewed to the left...so this is not symmetrical
Neighborhood B : the median is 3....the minimum is 1....so thats 2 spaces from the median...the maximum is 12....so thats 10 spaces from the median....these are not symmetrical especially since u have an outlier of 12....this is skewed to the right
Answer:
x =(-8+√-32)/6=(-4+2i√ 2 )/3= -1.3333+0.9428i
Step-by-step explanation:
I need help to solve this problems can somebody help me
